A person applies a force of 200 N over 1.5 m to a jack. The jack exerts a 1000-N force on a car a distance of 0.02 m. What is th
1 answer:
Answer:
The efficiency rating of the jack is 0.067.
Explanation:
We have, a person applies a force of 200 N over 1.5 m to a jack. The jack exerts a 1000-N force on a car a distance of 0.02 m.
It is required to find the the efficiency rating of the jack. It is equal to the ratio of output work to the ratio of input work. So,
Thus, the efficiency rating of the jack is 0.067.
You might be interested in
<u>Answer:</u> The moles of added to the system is 7.13 moles
<u>Explanation:</u>
We are given:
Moles of at equilibrium = 1.00 moles
Moles of at equilibrium = 1.00 moles
Moles of at equilibrium = 2.40 moles
Moles of at equilibrium = 2.40 moles
Volume of the container = 4.00 L
Concentration is written as:
The given chemical equation follows:
The expression of for above equation follows:
Putting values in above equation, we get:
To calculate the number of moles for given molarity, we use the equation:
Molarity of CO = 0.791 mol/L
Volume of solution = 4.00 L
Putting values in above equation, we get:
Extra moles of CO = (3.164 - 2.40) = 0.764 moles
Let the moles of needed be 'x' moles.
Now, equilibrium gets re-established:
Initial: 1.00 1.00 2.40 2.40
At eqllm: (0.236+x) 0.236 3.164 3.164
Again, putting the values in the expression of , we get:
Hence, the moles of added to the system is 7.13 moles