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alexgriva [62]
3 years ago
11

A person applies a force of 200 N over 1.5 m to a jack. The jack exerts a 1000-N force on a car a distance of 0.02 m. What is th

e efficiency rating of the jack? HINT: Use work formula first to solve for WORKout and again for WORKin...then use efficiency formula.
Chemistry
1 answer:
xz_007 [3.2K]3 years ago
6 0

Answer:

The efficiency rating of the jack is 0.067.

Explanation:

We have, a person applies a force of 200 N over 1.5 m to a jack. The jack exerts a 1000-N force on a car a distance of 0.02 m.

It is required to find the the efficiency rating of the jack. It is equal to the ratio of output work to the ratio of input work. So,

\eta=\dfrac{1000\times 0.02}{200\times 1.5}\\\\\eta=0.067

Thus, the efficiency rating of the jack is 0.067.

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When an ionic compound dissolves in water:
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Answer:

d. each of the above (A, B, and C) occurs.

Explanation:

When an ionic species dissolves in water , the ionic compound dissociates into cation and anion , and the cation interacts with the negative end of the water molecules , and the anion interacts with the positive end of the water molecule .

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What volume will 1,27 moles of helium gas occupy at 63°C and 75.2 kPa?
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Answer:

47.34L

Explanation:

Using the general gas equation as follows:

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T = temperature (K)

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V = nRT/P

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