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marissa [1.9K]
3 years ago
10

If body fat has a density of .94g/mL and 4.0L of fat is removed, how many pounds of fat were removed?

Chemistry
1 answer:
Vlad1618 [11]3 years ago
7 0

Answer:

8.3lb of fat were removed

Explanation:

To solve this problem we need to convert the liters of fat removed to mL. Using the mL and density we can find the grams. To convert grams to pounds we must use (1lb = 453.592g):

<em>mL fat:</em>

4.0L * (1000mL / 1L) = 4000mL

<em>g fat:</em>

4000mL * (0.94g / mL) = 3760g of fat

<em>lb fat:</em>

3760g of fat * (1lb / 453.592g) =

<h3>8.3lb of fat were removed</h3>
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Carbon disulfide burns with oxygen to form carbon dioxide and sulfur dioxide in the following manner: CS2 + 3O2 → CO2 + 2SO2 If
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A sheet of polyethylene 1.5-mm thick is being used as an oxygen barrier at a temperature of 600K. If the flux is 2.48 x 10-5 kg/
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Complete Question

The complete question is shown on the first uploaded image  

Answer:

The concentration of  high-pressure side is  C_1 =   0.722 \ kg/m^3

Explanation:

From the question we are told that

    The thickness of the polyethylene is  d  =  1.5 \ mm = 0.0015 \ m

     The  temperature is  T  =  600 \   K

      The flux is  JA  =  2.48 *10^{-5} \  kg/m^2\cdot s

      The concentration on the low-pressure side is  C_2 =  0.5 \ kg/m^3

       The initial diffusivity  is  D_o  =  6.2 *10^{-4} \ m^2 /s

       The activation energy for  diffusion is   Q_d  =  41 \ kJ /mol  =  41*10^3 J /mol

Generally the diffusivity  of the oxygen at 600 K can be  mathematically evaluated  as

        D   = D_o * e^{- \frac{Q_d}{R * T  } }  

substituting values  

         D   = 6.2*10^{-4} * e^{- \frac{41 *10^3}{8.314 * 600  } }  

          D   = 1.671 *10^{-7} \ m^2 /s  

Generally the flux is mathematically represented as

          JA  =  D  *  \frac{C_1 -C_2}{d}

Where C_1 is the concentration of oxygen at the higher side

       So  

             C_1 =    d  * \frac{JA}{D}  + C_2

substituting values  

             C_1 =    0.0015   * \frac{2.48*10^{-5}}{1.671*10^{-7}}  + 0.5

              C_1 =   0.722 \ kg/m^3

 

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It is totally wrong to assert that when the acidity of a solution increases, the pH of the solution will increase

The right answer is that when the acidity of a solution increases, the pH value decreases.

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