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4 years ago

Select all of the answers that apply.

2 answers:

6 0

The answers are --

a) wind direction
b) wind speed
e) intensity of precipitation
f) location of precipitation

lbvjy [14]4 years ago

6 0

Select all of the answers that apply.

The Doppler radar can tell you many things about the weather, like .

wind direction
wind speed
humidity
temperature
intensity of precipitation
location of precipitation
air pressure

(the ones that are bolded are the correct answers...)

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The area vector of a square loop of 5 turns of a conductor each with side length of 0.2 m carrying a current of 2 A is antiparal

Anon25 [30]

Answer:

$M= 0.4 Am^2$

Explanation:

From the question we are told that:

Number of turns $N=5$ $N=5$

Conductor each with side length $L=0.2m$

Current $I=2A$

Magnetic field $B=50.0T$

Generally the equation for the total magnetic moment M is mathematically given by

$M = current * area$

$M= I * A$

$M = 2 * (5* 0.2*0.2)$

$M = 2 * 0.2$

$M= 0.4 Am^2$

3 0

3 years ago

An object is 30 cm in front of a converging lens with a focal length of 10 cm. Use ray tracing to determine the location of the

Aleksandr-060686 [28]

Answer:

i). Inverted

ii). Magnification of the image = -0.5

iii). Real

Explanation:

As shown in the ray diagram attached,

An object AB has been placed in front of converging lens (convex lens) at u = 30 cm.

F (Focus) of the lens is at 10 cm. So F = 10 cm

By analyzing the ray diagram we can measure the distance of the image on the other side of the lens (By counting the small blocks of the graph)

V = 15 cm

Characteristics of the image is:

i) Inverted

ii) Magnification of the image = $-\frac{v}{u}=-\frac{15}{30}$

= -0.5

ii) Real

4 0

3 years ago

How much work is done if a force of 20 N moves an object a distance of 6 m?

Nesterboy [21]

Explanation:

W=F×s

w=20N×6m=120J

W=120J

3 0

3 years ago

The half-wave rectifier circuit of vs(t) = 170 sin(377t) V and a load resistance R = 15Ω. Determine: a. The average load current

irina1246 [14]

Answer:

a average load current = 11.33 A

b rms load current = 8.02A

c true power =962.64 W

d apparent power =962.64 W

e. power factor cosθ =1

Explanation:

Vs (t) = 170 sin(377t) v

Vm =170v

Vrms = 170/√2 =120.23 v

Im = Vm/R = 170/15 = 11.33 A

Irms = Im/ √2 = 11.33/√2 =8.02A

Resistors are electronic components that consume energy

the power in a resistor is given by P =IVcosθ ; in a resistor cosθ =1

P =IV

The electrical power consumed by a resistance, (R) is called the true or real power

and is obtained by multiplying the rms voltage with the rms current.

P= Vrms × Irms

120.03×8.02

P= 962.64 W ; true power

apparent power = Vrms × Irms

=120.03×8.02

= 962.64W ; apparent power

power factor cosθ = true power/ apparent power

cosθ = 962.64/962.64

cosθ = 1

For the purely resistive circuit, the power factor is 1 , because the reactive power is equal to zero (0).

6 0

4 years ago

Read 2 more answers

What's the minimum Out PUT WORK required to raise 14,0m3 of water 26.0m?

BartSMP [9]

Answer:

3.57 MJ

Explanation:

ASSUMING it's fresh water with density of 1000 kg/m³

W = ΔPE = mgΔh = 14.0(1000)(9.81)(26.0) = 3,570,840 J

Salt water would require more.

3 0

3 years ago