Answer:
OCl− + H2O ⇌ HOCl + OH−
Explanation:
Sodium hypochlorite is a corrosive base with pH 13, that will react with water in a neutralization process to finally obtein hypochlorous acid. This acid has a great disinfectant effect in water.
Answer:
(a) The normal freezing point of water (J·K−1·mol−1) is
(b) The normal boiling point of water (J·K−1·mol−1) is ![-109Jmole^-^1K^-^1](https://tex.z-dn.net/?f=-109Jmole%5E-%5E1K%5E-%5E1)
(c) the chemical potential of water supercooled to −5.0°C exceed that of ice at that temperature is 109J/mole
Explanation:
Lets calculate
(a) - General equation -
=
= ![-\frac{\Delta H}{T}](https://tex.z-dn.net/?f=-%5Cfrac%7B%5CDelta%20H%7D%7BT%7D)
→ phases
ΔH → enthalpy of transition
T → temperature transition
=![= -\frac{\Delta_fH}{T_f}](https://tex.z-dn.net/?f=%3D%20-%5Cfrac%7B%5CDelta_fH%7D%7BT_f%7D)
=
(
is the enthalpy of fusion of water)
= ![-22Jmole^-^1k^-^1](https://tex.z-dn.net/?f=-22Jmole%5E-%5E1k%5E-%5E1)
(b) ![(\frac{d\mu(g)}{dT})_p-(\frac{d\mu(l)}{dT})_p= -\frac{\Delta_v_a_p_o_u_rH}{T_v_a_p_o_u_r}](https://tex.z-dn.net/?f=%28%5Cfrac%7Bd%5Cmu%28g%29%7D%7BdT%7D%29_p-%28%5Cfrac%7Bd%5Cmu%28l%29%7D%7BdT%7D%29_p%3D%20-%5Cfrac%7B%5CDelta_v_a_p_o_u_rH%7D%7BT_v_a_p_o_u_r%7D)
=
(
is the enthalpy of vaporization)
= ![-109Jmole^-^1K^-^1](https://tex.z-dn.net/?f=-109Jmole%5E-%5E1K%5E-%5E1)
(c)
=![-S_m\DeltaT](https://tex.z-dn.net/?f=-S_m%5CDeltaT)
°
°
=
°
°![C)]](https://tex.z-dn.net/?f=C%29%5D)
ΔT
°
°![C)=-Sm\DeltaT [\mu(l,0](https://tex.z-dn.net/?f=C%29%3D-Sm%5CDeltaT%20%5B%5Cmu%28l%2C0)
![\Delta\mu=(21.995Jmole^-^1K^-^1)\times (-5K)](https://tex.z-dn.net/?f=%5CDelta%5Cmu%3D%2821.995Jmole%5E-%5E1K%5E-%5E1%29%5Ctimes%20%28-5K%29)
= 109J/mole
Answer:
8.20 % → Percent yield reaction
Explanation:
To find the percent yield of reaction we apply this:
(Produced yield / Theoretical yield) . 100 = %
Produced yield = 112.9 g
Theoretical yield = 1375.5 g
We replace → (112.9g / 1375.5 g) . 100
8.20 % → Percent yield reaction