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kompoz [17]
3 years ago
13

In a calorimetry experiment, a salt is dissolved in water within an insulating container. The temperature of the solution (surro

undings) decreases from 25°C to 14°C. Given that the mass of the solution is 120 g, and the specific heat of the solution is 3.18 J/g°C, calculate the enthalpy change (in kJ) for the dissolving process. Be sure to give the correct sign for your answer, and identify the dissolving process as endothermic or exothermic. Group of answer choices
Chemistry
1 answer:
Stels [109]3 years ago
7 0

Answer:

Explanation:

heat released  by the solution

= 120 x 3.18 x ( 25 - 14 )

= 4197.6 J

= 4.1976 kJ

This is the heat gain by the salt

so enthalpy change = +  4.1976 kJ

because there is increase  in enthalpy

It is endothermic process .

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Which Of These Periods Contain Elements With Electrons s,p,d and f orbitals? Periods 1-3 Periods 1-4
Elanso [62]
The answer would be periods 6-7 :)
7 0
3 years ago
A gas mixture containing oxygen, nitrogen, and carbon dioxide has a total pressure of 32.5 kPa. If Po2 =
HACTEHA [7]

Answer:

A gas mixture containing oxygen, nitrogen, and carbon dioxide has a total pressure of 32.5 kPa.

<u>The pressure for oxygen is 3 kPa</u>

Explanation:

According to Dalton's Law of Partial Pressure total exerted by the mixture of non-reacting gases is equal to sum of the partial pressure of each gas.

P_{total}=P_{1}+P_{2}+P_{3}

So,

For , a gas mixture containing oxygen, nitrogen, and carbon dioxide has a total pressure:

P_{total}=P_{O_{2}}+P_{N_{2}}+P_{CO_{2}}

P_{total} = 32.5kPa

P_{O_{2}} = 6.5kPa

P_{N_{2}} = 23.0kPa

Insert the values in :

P_{total}=P_{O_{2}}+P_{N_{2}}+P_{CO_{2}}

32.5 kPa = 6.5 kPa + 23.0 kPa +P_{CO_{2}}

32.5 kPa = 29.5 kPa +P_{CO_{2}}

P_{CO_{2}}= 32.5 - 29.5

P_{CO_{2}}= 3kPa

6 0
3 years ago
A 1.67-g sample of solid silver reacted in excess chlorine gas to give a2.21-g sample of pure solid Agcl.The heat given off in t
kotegsom [21]

<u>Given:</u>

Mass of Ag = 1.67 g

Mass of Cl = 2.21 g

Heat evolved = 1.96 kJ

<u>To determine:</u>

The enthalpy of formation of AgCl(s)

<u>Explanation:</u>

The reaction is:

2Ag(s) + Cl2(g) → 2AgCl(s)

Calculate the moles of Ag and Cl from the given masses

Atomic mass of Ag = 108 g/mol

# moles of Ag = 1.67/108 = 0.0155 moles

Atomic mass of Cl = 35 g/mol

# moles of Cl = 2.21/35 = 0.0631 moles

Since moles of Ag << moles of Cl, silver is the limiting reagent.

Based on reaction stoichiometry: # moles of AgCl formed = 0.0155 moles

Enthalpy of formation of AgCl = 1.96 kJ/0.0155 moles = 126.5 kJ/mol

Ans: Formation enthalpy = 126.5 kJ/mol


6 0
3 years ago
Read 2 more answers
Convert 72g of O2 to moles
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Moles = mass / molar mass
molar mass of O2 is 32
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