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ankoles [38]
3 years ago
8

Which type of heat exchanger shell and tube or plate heat exchanger is suitable for evaporation?

Chemistry
1 answer:
klasskru [66]3 years ago
5 0

Answer:

shell and tube type heat exchanger

Explanation:

for evaporation the shell and tube type heat exchanger is best suited.

  • in the plate heat exchanger there is gaskets in between every part so this part become weak part in heat echanger and there is possibilities of leakage through this part, there is no such problem in shell and tube type.
  • the plate type cant be used when there is high temperature and high pressure drop but shell and tube type can be used
  • in evaporation there the liquids change into vapors due to which there is sudden change in pressure and in which plate type is not used because there is chances of leakage
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Explanation:

The term "organic compound" refers to the group of carbon-containing compounds such as glucose (C6H12O6), Propane (C3H8), ethyne (C2H2) etc, where the carbon atoms in them are covalently bounded to other atoms such as hydrogen, oxygen, phosphorus, nitrogen etc

Examples of organic compounds are ethanol (C2H5OH), ethylamine (C2H5NH2) etc.

Thus, organic compound are carbon-containing compounds with covalent bonds to other atoms.

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Explanation:

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3 years ago
Write any two uses of fractinal distillation​
lubasha [3.4K]

Answer:

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Given the propane molecule C3H8(g)! a) What is the balanced equation for the combustion of propane in O2?(20 pts.) b) What is th
lubasha [3.4K]

Answer:

The answer to your question is below

Explanation:

Propane = C₃H₈

Process

1.- Write the chemical reaction

                     C₃H₈  +  O₂   ⇒   CO₂  +  H₂O

balanced chemical reaction

                      C₃H₈  +  5O₂   ⇒  3CO₂  +  4H₂O

               Reactants      Elements     Products

                      3                    C                  3

                      8                    H                  8

                     10                    O                 10

b) Standard enthalpy

Propane                  -104.7 kJ/mol

Oxygen                         0   kJ/mol

Carbon dioxide      -393.5 kJ/mol

Water                      -241.8 kJ/mol

ΔH° = ∑ΔH° products - ∑H° reactants

ΔH° = 3(-393.5) + 4(-241.8) - [(-104.7) + 0]

-Simplification

ΔH° = -1180.5 kJ/mol - 967.2 kJ/mol + 104.7 kJ/mol

ΔH° = - 2042.5 kJ/mol

This reaction is exothermic because ΔH° is negative.

4 0
3 years ago
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