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2 years ago

Which type of heat exchanger shell and tube or plate heat exchanger is suitable for evaporation?

Chemistry

1 answer:

klasskru [66]2 years ago

5 0

Answer:

shell and tube type heat exchanger

Explanation:

for evaporation the shell and tube type heat exchanger is best suited.

in the plate heat exchanger there is gaskets in between every part so this part become weak part in heat echanger and there is possibilities of leakage through this part, there is no such problem in shell and tube type.
the plate type cant be used when there is high temperature and high pressure drop but shell and tube type can be used
in evaporation there the liquids change into vapors due to which there is sudden change in pressure and in which plate type is not used because there is chances of leakage

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Name the compound formed when a copper cation that has a 2+ charge combines with a bromine anion that has a 1- charge.

Lynna [10]

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Alexxandr [17]

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3 years ago

How many Faradays of electricity are carried by 1.505×10^23 electronsk

aksik [14]

Mole of electron required by $1.505 *10^{23}$ mole is $2.5* 10 ^{-1}$

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There is one mole of electron required for 1 Faraday of electricity.

Avogadro constant is $6.02*10^{23}$

Mole of electron can be calculated by dividing the number of electron by avogadro's constant.

= $\frac{1.505*10^{23} }{6.02*10^{23} }$

= $2.5* 10^{-1} Faraday of electricity$

Therefore, it requires $2.5*10^{-1}$ Faraday of electricity for the $1.505 * 10^{23} mole.$

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2 years ago

1.00 L of a gas at STP is compressed to 473mL. What is the new pressure of gas?

Ratling [72]

Hello!

1.00 L of a gas at STP is compressed to 473 mL. What is the new pressure of gas?

We have the following data:

Vo (initial volume) = 1.00 L

V (final volume) = 473 mL → 0.473 L

Po (initial pressure) = 1 atm (pressure exerted by the atmosphere - in STP)

P (final pressure) = ? (in atm)

We have an isothermal transformation, that is, its temperature remains constant, if the volume of the gas in the container decreases, so its pressure increases. Applying the data to the equation Boyle-Mariotte, we have:

$P_0*V_0 = P*V$