Answer:
v = 20 m/s
Explanation:
Given that :
Initial Velocity of cars (u) = 0
Car with smaller mass = m
Car with larger mass = 2m
Final velocity of smaller mass = v
Final velocity of larger mass v2 = 10
Using the relation :
Initial momentum = final momentum
m1u1 + m2u2 = m1v1 + m2v2
Since u = 0
m1v1 + m2v2 = 0
mv + 2m * 10 = 0
mv + 20m = 0
mv = 20m
v = 20m / m
v = 20
Final velocity of larger mass car will be 20 m/s
260 meters im pretty sure because rate*time=distance
Answer:
Part a)
Part b)
Explanation:
Diameter of the circle = 24 ft
Diameter = 731.52 cm = 7.3152 m
now the horse complete 144 trips in one hour
so time to complete one trip is given as
now the speed of the horse is given as
Part a)
Now we know that the power is defined as rate of work done
it is given as
Part b)
Work done to climb up to 3 m height is given by
now we have
now we know that 1 HP = 746 Watt
so we have
Answer:
1.6 meters east
Explanation:
Note: Image attached.
As we can see on the data, Anita is further from the puddle than Nick. Additionally, the distances relatives to the center of the puddle allow us to now the lenght of the rope which is the sum of these two, 9.2 meters. We also know that the knot is at the middle of the rope, so it means it is at 4.6 meters of both Anita and Nick. Now what is next? Well, we now have everything we know. We have the distance between Anita and the puddle and we also know the distance between Anita and the knot (4.6 meters). We just need to subtract the distance to the knot from the distance to the puddle which is equal to 1,6 meters east direction.
If you guys have any questions, just let me know.
Answer:
32I
Explanation:
Data provided in the question:
Rotational inertia of a sphere about an axis through the center = I
Now,
Let the radius of the sphere be 'R'
also,
Rotational inertia = MR²
Here,
M is the mass
Mass = Density ÷ Volume
Volume of sphere =
Therefore,
M = Density ×
Thus,
I =
Now for the sphere of radius twice the radius i.e 2R
Volume =
Since the density is same
Mass =
Thus,
I' =
or
I' = 8 × 4 ×
or
I' = 32I