Answer:
B. Technician B only
Explanation:
An oscilloscope can be used to check the output signal of an optical sensor. The oscilloscope has the functioning of viewing the results in the form of waveform and its time scale settings can be altered to meet the requirements of the results.
A voltmeter cannot be <u>directly</u> used to monitor the output signal of an optical sensor. But a <u>digital multi-meter</u> can be used to check an optical sensor if the digital multi-meter is set on AC - Volt reading mode.
Answer:
Industries outlook is uncertain
Explanation:
Competitive pressures stemming from the threat of entry are stronger when the industry's outlook is uncertain or highly risky, entry barriers are low, and very few existing industry members are looking to expand their market reach by entering product segments or geographic areas where they currently do not have a presence. entry barriers are low, the pool of entry candidates is large, and existing industry members are earning good profits. there are fewer than 10 entry candidates with the potential to hurdle the industry's barriers to entry. t is difficult or costly for a customer to switch to a new brand, the total dollar investment needed to enter the market successfully exceeds $5 million, and existing governmental regulations impose significant cost and compliance burdens on industry members. buyers have strong brand preferences and high degrees of loyalty to their preferred brand and when it takes new entrants less than 5 years to secure attractive amounts of space on retailers' shelves and build a well-recognized brand name.
Answer:
(a) ![W=-19.25J](https://tex.z-dn.net/?f=W%3D-19.25J)
(b) ![W=-52.8J](https://tex.z-dn.net/?f=W%3D-52.8J)
Explanation:
Hello.
(a) In this case, since the initial volume is 18.5 dm³ and the final volume is 21 dm³ (18.5 +2.5), we can compute the work at constant pressure as shown below:
![W=-P\Delta V=-7.7kPa*\frac{1000Pa}{1kPa} (21dm^3-18.5dm^3)*\frac{1m^3}{1000dm^3}\\ \\W=-19.25J](https://tex.z-dn.net/?f=W%3D-P%5CDelta%20V%3D-7.7kPa%2A%5Cfrac%7B1000Pa%7D%7B1kPa%7D%20%2821dm%5E3-18.5dm%5E3%29%2A%5Cfrac%7B1m%5E3%7D%7B1000dm%5E3%7D%5C%5C%20%5C%5CW%3D-19.25J)
Which is negative as it expands against the given pressure.
(b) Moreover, of the process is carried out reversibly, the pressure can change, therefore, we need to compute the work via:
![W=nRTln(\frac{V_1}{V_2} )](https://tex.z-dn.net/?f=W%3DnRTln%28%5Cfrac%7BV_1%7D%7BV_2%7D%20%29)
Whereas the moles are computed from the given mass of argon:
![n=6.56g*\frac{1mol}{39.95g}=0.164mol](https://tex.z-dn.net/?f=n%3D6.56g%2A%5Cfrac%7B1mol%7D%7B39.95g%7D%3D0.164mol)
Thus, the work is:
![W=0.164mol*8.314\frac{J}{mol*K} *305Kln(\frac{18.5dm^3}{21dm^3} )\\\\W=-52.8J](https://tex.z-dn.net/?f=W%3D0.164mol%2A8.314%5Cfrac%7BJ%7D%7Bmol%2AK%7D%20%2A305Kln%28%5Cfrac%7B18.5dm%5E3%7D%7B21dm%5E3%7D%20%29%5C%5C%5C%5CW%3D-52.8J)
Regards.
Answer:mile
Explanation: heres a hint think aboyt the distance between your house to school