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Len [333]
3 years ago
5

A cyclist maintains a constant velocity of 5 m/s headed away from point A. At some initial time, the cyclist is 247 m from point

A. What will his displacement be in meters from his starting position after 52 seconds?
​
Physics
1 answer:
worty [1.4K]3 years ago
5 0

260 meters im pretty sure because rate*time=distance

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Khaled said the North star is special because it appears all over the world and its changes position.
saw5 [17]
False the North Star never changes it position
3 0
3 years ago
What will a spring scale read for the weight of a 58.0-kg woman in an elevator that moves in free fall?
solniwko [45]

Answer:

0 N

Explanation:

The elevator is under free fall. So, when a body is under free fall, the acceleration is only due to gravity. So, the acceleration of the elevator or the woman inside it, is acceleration due to gravity in the downward direction.

The spring scale gives the value of the normal force acting on the woman and doesn't give the exact weight of the woman. Under normal conditions, when the spring scale is at rest, then the upward normal force equals the weight and hence weight of a body is equal to the normal force acting on the body.

But, here, the body is not at rest. Weight\tex](mg)[/tex] acts in the downward direction and normal force(N) acts in the upward direction. The woman is moving down with acceleration equal to acceleration due to gravity(g)

So, we apply Newton's second law on the woman.

\textrm{Net force} = \textrm{mass}\times \textrm{acceleration}\\F_{net}=ma

Net force is equal to the difference of the downward force and upward force.

F_{net}=mg-N

Now, F_{net}=ma

mg-N=mg\\N=mg-mg=0

Therefore, the reading on the spring scale is 0 N.

5 0
3 years ago
Estimate the radiation pressure due to a bulb that emits 25 W {\rm W} of EM radiation at a distance of 9.5cm \;cm from the cente
madam [21]

Answer:

7.3*10^{-7}  \frac{N}{m^2}

Explanation:

\frac{25}{(4*\pi*(0.095)^{2}*3*10^8 }

Hope this is right and helps!

8 0
3 years ago
A force of 100.0N is appliesd to an object of mass 85.0kg. what is the object acceleration
kumpel [21]

Answer:

<h2>1.18 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{100}{85}  =  \frac{20}{17}  \\  = 1.176470...

We have the final answer as

<h3>1.18 m/s²</h3>

Hope this helps you

3 0
3 years ago
What is your acceleration while sitting in your chair. the latitude of corvallis is 44.4˚.?
marta [7]
 <span>You can start with the equations you know 

a=v^2/r = (2pi*r/T)^2/r = 4pi^2r/T^2 

Radius of earth (R) = 6378.1 km 
Time in one day (T) = 86400 seconds 
Latitude = 44.4 degrees 

If you draw a circle and have the radius going out at a 44.4 degree angle above the center you can then find the r. 

r=Rcos(44.4) 
r=6378.1cos(44.4) 
r= 4556.978198 km or 4556978 m 

Now you can plug this value into the acceleration equation from above... 

a= 1.8*10^8/7.47*10^9 
a= .0241 m/s^2 </span>
8 0
3 years ago
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