A)We know the formula of the angular speed is ω = 2π / TWhere T is the time period.When second hand completes one revolution then the time taken is 60s.So T = 60sThen the angular speed of the second hand is ω= 2π / (60s) = 0.1047 rad/sb)When the minute hand completes one revolution the time taken is T = 1 hr = 3600sThen the angular speed of the minute hand is ω =(2π) / (3600s) = 0.001745 rad/sc)When the hour hand completes one revolution then the timeperiod is T = 12hrs = (12)(3600)sThen the angular speed of the hour hand is ω =(2π) / [(12)(3600)s] = 1.45444 x 10^-4 rad/s
No. The correct one would be D .
Answer: The speed is not constant and the object is performing a non uniform circular motion
Explanation:
Let's begin by explaining that the centripetal force is proportional to the centripetal acceleration of an object moving in circular motion is given by the following equation:
Where:
is the velocity
is the radius of the circle
In uniform circular motion, <u>the centripetal acceleration vector is always perpendicular to the velocity vector</u>, hence, the speed (the magnitude of velocity vector) is constant.
However, if a component of the centripetal acceleration vector is not perpendicular (is parallel to the velocity vector): the speed is not constant, the net force acting on the object will not be perpendicular to its motion and we will be dealing with <u>non uniform circular motion.</u>
It is important to note that in this situation the motion needs a tangential force, as well. Being the tangential acceleration proportional to and the angular acceleration :
Average kinetic energy hope this helps!