We can use the Pythagorean theorem to solve for the perimeter of the kite.
a² + b² = c²
3² + 4² = UV²
9 + 16 = UV²
25 = UV²
√25 = √UV²
5 = UV
In the kite, adjacent sides are the same so UV = VW
3² + 9² = UX²
9 + 81 = UX²
90 = UX²
√90 = √UX²
9.49 ≈ UX or 3√10 ≈ UX
Now, add to find the perimeter.
5 + 5 + 9.49 + 9.49 or 5 + 5 + 3√10 + 3√10
28.98 or 10 + 6√10
Therefore, the perimeter is approximately 28.98 or 10 + 6√10
Best of Luck!
0.1/2.1 I hope that helps
Answer:
d. 128 cm^3
Step-by-step explanation:
to find the volume its length time width times heights; so 4 cm times 4 cm time 4 cm which is 64. Since the dice are the same size you add 64 cm^3 to 64 cm^3 to get 128 cm^3
yes, because 46.2/6 = 7.7 ounces and 107.8/14 = 7.7 ounces
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