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Ksju [112]
3 years ago
12

I really need your help

Chemistry
1 answer:
PilotLPTM [1.2K]3 years ago
6 0

Answer:

Terrestrial

                   -20 to 30 degrees celsius average

                        (20 – 35 inches) of rain per year.

                     PLANTS: Grasses dominate temperate grasslands. Trees and large shrubs are rarely found in grassland areas

                gazelles, zebras, rhinoceroses, wild horses, lions, wolves, prairie dogs, jack rabbits, deer, mice, coyotes, foxes, skunks, badgers, blackbirds, grouses, meadowlarks, quails, sparrows, hawks, owls, snakes, grasshoppers, leafhoppers, and spiders.

            Grasslands are also known as prairies, pampas, steppes, and savannas.

Explanation:

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Do your structures resemble the following?<br> H-C=C-H
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For the HCCH Lewis structure you'll need to form a triple bond between the two carbon atoms. Hydrogen atoms only need two electrons for a full outer shell. There are a total of 10 valence electrons for the HCCH Lewis structure.

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What is the atmospheric pressure?
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The air pressure at sea level is about 14.7 pounds per square inch (psi). For every foot above sea level, the air pressure drops about 0.0005263 psi. According to this information, at about what height above sea level is the air pressure 13.2 psi?

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3 years ago
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Suppose that the carbon atom pictured here as a reactant had already formed a double bond with another carbon atom. how many hyd
ivanzaharov [21]
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4 years ago
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If 28.0 grams of Pb(NO3)2 react with 18.0 grams of NaI, what mass of PbI2 can be produced? Pb(NO3)2 + NaI → PbI2 + NaNO3
ss7ja [257]

Answer:- 27.7 grams of PbI_2 are produced.

Solution:- The balanced equation is:

Pb(NO_3)_2+2NaI\rightarrow PbI_2+2NaNO_3

let's convert the grams of each reactant to moles and calculate the grams of the product and see which one gives least amount of the product. This least amount would be the answer as the least amount we get is from the limiting reactant.

Molar mass of Pb(NO_3)_2 = 207.2+2(14.01)+6(16)  = 331.22 gram per molmolar mass of NaI = 22.99+126.90 = 149.89 gram per molMolar mass of [tex]PbI_2 = 207.2+2(126.90) = 461 gram per mol

let's do the calculations for the grams of the product for the given grams of each of the reactant:

28.0gPb(NO_3)_2(\frac{1molPb(NO_3)_2}{331.22gPb(NO_3)_2})(\frac{1molPbI_2}{1molPb(NO_3)_2})(\frac{461gPbI_2}{1molPbI_2})

= 39.0gPbI_2

18.0gNaI(\frac{1molNaI}{149.89gNaI})(\frac{1molPbI_2}{2molNaI})(\frac{461gPbI_2}{1molPbI_2})

= 27.7gPbI_2

From above calculations, NaI gives least amount of PbI_2, so the answer is, 27.7 g of PbI_2 are produced.

8 0
3 years ago
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