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Goryan [66]
3 years ago
8

What is metallurgy?

Chemistry
1 answer:
garri49 [273]3 years ago
5 0

Answer:

B science of working with metals

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A new penny has a mass of 2.49 grams and occupies 0.349 cm cubed. If pure copper has a density of 8.96 g/cm cubed, is the new pe
lys-0071 [83]

Answer: The new penny is not pure copper

Explanation:

Density \rho is defined as a relation between the mass m and the volume V:

\rho=\frac{m}{V}

Now, we are told the density of pure copper is:

\rho_{copper}=8.96 g/cm^{3}

And we are given the mass and volume of the new penny, with which we can calculate its density:

\rho_{penny}=\frac{m_{penny}}{V_{penny}}=\frac{2.49 g}{0.349 cm^{3}}

\rho_{penny}=7.13 g/cm^{3} As we can see the density of this penny is not equal to the density of pure copper, hence the new penny is not pure copper.

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4 years ago
How does the law of conservation of mass apply this reaction mg + HCl -- H2 + mgcl2
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The correct answer is D hydrogen and chlorine need to be balanced there's an equal amount of magnesium on each side. I just took the test and got the correct answer.

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3(so)4 how many sulfur atoms and oxygen
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There is 3 sulfur and 12 oxygen atoms

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The amount of water that evaporates from earth is
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<span>Evaporation from the oceans is the primary mechanism supporting the surface-to-atmosphere portion of the water cycle</span>
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Write the empirical formula for at least four ionic compounds that could be formed from the following ions
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Answer:

NH₄CN,  NH₄IO₃,  Fe(CN)₃,  Fe(IO₃)₃

Explanation:

Cations (positively charged ions) can only form ionic bonds with anions (negatively charged ions). However, you can't just simply put one cation and one anion together to form a compound. Each compound needs to been neutral, or have an overall charge of 0. When cations and anions do not have charges that perfectly cancel, you need to modify the amount of each ion in the compound.

1.) NH₄CN

-----> NH₄⁺ and CN⁻

-----> +1 + (-1) = 0

2.) NH₄IO₃

-----> NH₄⁺ and IO₃⁻

-----> +1 + (-1) = 0

3.) Fe(CN)₃

-----> Fe³⁺ and CN⁻

-----> +3 + (-1) + (-1) + (-1) = 0

4.) Fe(IO₃)₃

-----> Fe³⁺ and IO₃⁻

-----> +3 + (-1) + (-1) + (-1) = 0

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2 years ago
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