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Art [367]
2 years ago
7

Which of the following halogens has the weakest attraction for electrons?

Chemistry
1 answer:
Leokris [45]2 years ago
4 0

Answer:

I

Explanation:

Among the halogens given in this problem, iodine has the lowest attraction for electrons.

This property is known as electronegativity.

Electronegativity is expressed as the relative tendency with which the atoms of the element attracts valence electrons in a chemical bond.

  • As you go down the periodic group the electronegativity decreases.
  • The most electronegative element on the periodic table is fluorine.
  • Down the group, iodine is the least electronegative
  • This is due to the large size of its atom.
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26 g of zinc combines with 12.8 g of sulfur. What is the empirical formula of zinc sulfide?
Alisiya [41]
Moles of Zn: 26 / 65 = 0.4
Moles of S: 12.8 / 32 = 0.4

Molar ratio of Zn : S = 1 : 1
Empircal formula: ZnS

The answer is C
7 0
3 years ago
How many grams of calcium chloride are dissolved in 5.65 liters of a 0.11 m solution of calcium choride?
Julli [10]
C = 0.11 mol
V = 5.65 L
n = ???

n = C*V
n = 0.11 * 5.65
n = 0.622 mols

1 mol of CaCl2 = 40 + 2*35.5 = 111 grams
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4 0
2 years ago
Abbreviated electron configuration for tellurium
Zinaida [17]

Answer:

The ground state electron configuration of ground state gaseous neutral tellurium is [Kr]. 4d10.

4 0
2 years ago
Which element forms steel when added to carbon?
dimaraw [331]
Nitrogen is your answer
7 0
3 years ago
6.5 Moles of Al reacts with 7.2 Moles of H2O What is the limiting reactant and calculate the Theoretical Yield?
SVEN [57.7K]

Answer:

H₂O is the limiting reactant

Theoretical yield of 240 g Al₂O₃ and 14 g H₂

Explanation:

Find how many moles of one reactant is needed to completely react with the other.

6.5 mol Al × (3 mol H₂O / 2 mol Al) = 9.75 mol H₂O

We need 9.75 mol of H₂O to completely react with 6.5 mol of Al.  But we only have 7.2 mol of H₂O.  Therefore, H₂O is the limiting reactant.

Now find the theoretical yield:

7.2 mol H₂O × (1 mol Al₂O₃ / 3 mol H₂O) × (102 g Al₂O₃ / mol Al₂O₃) ≈ 240 g Al₂O₃

7.2 mol H₂O × (3 mol H₂ / 3 mol H₂O) × (2 g H₂ / mol H₂) ≈ 14 g H₂

Since the data was given to two significant figures, we must round our answer to two significant figures as well.

4 0
2 years ago
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