The center-radius form<span> of the </span>circle<span> equation is in the format (x – h)</span>2<span> + (y – k)</span>2<span> = r</span>2<span>, with the center being at the point (h, k) and the radius being "r". Therefore, the center is located at point (1, -3) and is located in the fourth quadrant, last option. Hope this answers the question.</span>
Answer:
The most reasonable answer would likely be the first.
"When a pair of parallel lines is intersected by a third line, the alternate exterior angles are congruent."
Step-by-step explanation:
Area abc def cuase its 126-72+28=82 so abc def
1.
Domain: {-1, 0, 2, 3}
Range: {2, 4, 6}
2.
Ax+By=C: linear equation standard form
y=mx+b: slope intercept form
(y-y^1)=m(x-x^1): point slope form
The value of x is 0.65
<u>Step-by-step explanation:</u>
This solution is given by solving the given problem using BODMAS rule.
This means that the steps to be followed to find the solution should be in the order of BODMAS rule.
B- Bracket, O- of, D- Division, M- Multiplication, A- Addition, S- Subtraction.
This rule states that the 1st operation must be done for Brackets.
⇒ -3.75+2(-4x+6.1)-3.25 = 0
⇒ -3.75 -8x + 12.2 -3.25 = 0
The addition operation should be performed next and then followed by subtraction.
⇒ -8x -7+ 12.2 = 0
<u>To find the value of x :</u>
Keeping the x term alone on one side and moving the constants on other side,
⇒ -8x = -12.2 + 7
⇒ -8x = -5.2
⇒ x = 5.2/8
⇒ x = 0.65
