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Feliz [49]
3 years ago
15

What do an electron and a neutron have in common?

Physics
2 answers:
Harman [31]3 years ago
4 0

The correct answer to this question is B) Each particle exists inside an atom.

EXPLANATION:

Before going to answer this question , first we have to understand the nature of electron and neutron.

Electrons and neutrons are the subatomic particles which are present inside the atom.

Electron is that subatomic particle which is present in the extra nuclear part of the atom, and it moves around the nucleus in different permitted, stationary orbits. The charge of electron is negative.

The neutron is that subatomic particle which is present in the nuclear part of the atom along with protons. The charge of proton is positive and the neutron is neutral in nature.

Hence, the correct option of this question is that both electrons and neutrons are present inside the atom.

KIM [24]3 years ago
4 0

Answer: It's B

Explanation:

I just took the test

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The cornea behaves as a thin lens of focal lengthapproximately 1.80 {\rm cm}, although this varies a bit. The material of whichi
Keith_Richards [23]

Answer:

Explanation:

  a )

from lens makers formula

\frac{1}{f} =(\mu-1)(\frac{1}{r_1} -\frac{1}{r_2})

f is focal length , r₁ is radius of curvature of one face and r₂ is radius of curvature of second face

putting the values

\frac{1}{1.8} =(1.38-1)(\frac{1}{.5} -\frac{1}{r_2})

1.462 = 2 - 1 / r₂

1 / r₂ = .538

r₂ = 1.86 cm .

= 18.6 mm .

b )

object distance u = 25 cm

focal length of convex lens  f  = 1.8 cm

image distance  v   = ?

lens formula

\frac{1}{v} - \frac{1}{u} = \frac{1}{f}

\frac{1}{v} - \frac{1}{-25} = \frac{1}{1.8}

\frac{1}{v} = \frac{1}{1.8} -\frac{1}{25}

.5555 - .04

= .515

v = 1.94 cm

c )

magnification = v / u

= 1.94 / 25

= .0776

size of image = .0776 x size of object

= .0776 x 10 mm

= .776 mm

It will be a real image and it will be inverted.

 

5 0
3 years ago
Is this charging by induction or conduction?
sineoko [7]
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3 0
2 years ago
A 55.2 kg softball player moving 3.11 m/s slides across dirt with uk=0.310. How far does she slide before coming to a stop​
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Refer to the attachment

5 0
3 years ago
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3 years ago
A 35 N force makes a 10 degree angle with the positive x-axis. What is the magnitude of the vertical component of the force?
Snowcat [4.5K]

Answer:

6.07 N

Explanation:

Given that,

Force, F = 35 N

It makes 10 degree angle with the positive x-axis.

We need to find the magnitude of the vertical component of the force. It can be given by :

F_y=F\sin\theta\\\\=35\times \sin(10)\\\\=6.07\ N

So, the magnitude of the vertical component of the force is 6.07 N.

5 0
3 years ago
Read 2 more answers
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