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Feliz [49]
3 years ago
15

What do an electron and a neutron have in common?

Physics
2 answers:
Harman [31]3 years ago
4 0

The correct answer to this question is B) Each particle exists inside an atom.

EXPLANATION:

Before going to answer this question , first we have to understand the nature of electron and neutron.

Electrons and neutrons are the subatomic particles which are present inside the atom.

Electron is that subatomic particle which is present in the extra nuclear part of the atom, and it moves around the nucleus in different permitted, stationary orbits. The charge of electron is negative.

The neutron is that subatomic particle which is present in the nuclear part of the atom along with protons. The charge of proton is positive and the neutron is neutral in nature.

Hence, the correct option of this question is that both electrons and neutrons are present inside the atom.

KIM [24]3 years ago
4 0

Answer: It's B

Explanation:

I just took the test

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Answer: Mass of the object is  75 kg.
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In the winter activity of tubing, riders slide down snow covered slopes while sitting on large inflated rubber tubes. To get to
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Answer:

17304 J

Explanation:

Complete statement of the question is :

In the winter activity of tubing, riders slide down snow covered slopes while sitting on large inflated rubber tubes. To get to the top of the slope, a rider and his tube, with a total mass of 84 kg , are pulled at a constant speed by a tow rope that maintains a constant tension of 350 N .

Part A

How much thermal energy is created in the slope and the tube during the ascent of a 30-m-high, 120-m-long slope?

Solution :

T = tension force in the tow rope = 350 N

L  = length of the incline surface = 120 m

W_{t}  = work done by tension force = ?

The tension force acts parallel to incline surface, hence work done by tension force is given as

W_{t} = T L\\W_{t} = (350) (120)\\W_{t} = 42000 J

h = height gained by the rider = 30 m

m = total mass of rider and tube = 84 kg

Potential energy gained is given as

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Q = W_{t} - U\\Q = 42000 - 24696\\Q = 17304 J

7 0
3 years ago
The Event Horizon Telescope needs a 22 micro-arcsecond resolution to view the event horizon regions around black holes. If the a
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From Rayleigh Criterion

\theta=1.22\frac{\lambda}{D}\\\Rightarrow D=1.22\frac{\lambda}{\theta}\\\Rightarrow D=1.22\frac{1.3\times 10^{-3}}{22\times 10^{-6}\frac{\pi}{180\times 3600}}\\\Rightarrow D=14869817.395\ m

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<span>Work: W = Fd. 50(distance) multiplied by 90(force) would equal 4500 J or, answer D</span>
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