The two equations would be
32a+50b=14600
10a+40b=7000
To solve, we need to eliminate one variable.... let’s eliminate b
4(32a+50b=14600) —> 128a+200b=58400
-5(10a+40b=7000) —> -50a-200b=-35000
So when we add them together’ we get 78a = 23400
So solve that and a= 300, so class a tickets cost 300 euros each
Substitute a=300 into first equation in the system of equations at the beginning and 32(300)+50b=14600 —> 9600+50b=14600 —> 50b = 5000 or b= 100, so the cost for class b tickets is 100 euros each
Answer:
4x
Step-by-step explanation:
Because there are 4 x's.
Answer:
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Step-by-step explanation:
I just learned this, I believe that the answer is <span>a1=21;an=7⋅an−1</span>
