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hjlf
3 years ago
11

A 15.0 kg bucket is lowered vertically by a rope in which there is 188 N of tension at a given instant

Physics
1 answer:
saw5 [17]3 years ago
6 0

Answer: 2.72 m/s²

Explanation:

F = m(g + a)

188 = 15.0(9.81 + a)

188 = 147.15 + 15.0a

40.85 = 15.0a

a = 2.7233333... ≈ 2.72 m/s²

This is an upward acceleration as the force being applied is greater than that needed to maintain constant velocity. (147 N)

So even though the bucket is being lowered, it's rate of descent is decreasing  with time. If the acceleration continues for long enough, the bucket will begin to rise.

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Find the mass of an object if a 40 N of force causes the object to accelerate at 5.5 m/s/s
Murrr4er [49]

Answer:

<h3>The answer is 8 kg</h3>

Explanation:

The mass of the object can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{40}{5}  \\

We have the final answer as

<h3>8 kg</h3>

Hope this helps you

7 0
3 years ago
If the rectangular barge is 3.0 m by 20.0 m and sits 0.70 m deep in the harbor, how deep will it sit in the river?
leva [86]

The harbour contains salt water while the river contains fresh water. So assuming that the densities of fresh water and salt water are:

density (salt water) = 1029 kg / m^3

density (fresh water) = 1000 kg / m^3

The amount of water (in mass) displaced by the barge should be equal in two waters.

mass displaced (salt water) = mass displaced (fresh water)

Since mass is also the product of density and volume, therefore:

<span>[density * volume]_salt water = [density * volume]_fresh water                 ---> 1</span>

 

First we calculate the amount of volume displaced in the harbour (salt water):

V = 3.0 m * 20.0 m * 0.70 m

V = 42 m^3 of salt water

Plugging in the values into equation 1:

1029 kg / m^3 * 42 m^3 = 1000 kg/m^3 * Volume fresh water

Volume fresh water displaced = 43.218 m^3

 

Therefore the depth of the barge in the river is:

43.218 m^3 = 3.0 m * 20.0 m * h

<span>h = 0.72 m        (ANSWER)</span>

8 0
4 years ago
Pls answer I will make brainlist
Semenov [28]
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sentence: plucking the string of a guitar is an example of standing waves.

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3 0
3 years ago
A bicycle racer is going downhill at 11.0 m/s when, to his horror, one of his 2.25 kg wheels comes off when he is 75.0 m above t
alex41 [277]

Answer:

a.) Speed V = 29.3 m/s

b.) K.E = 1931.6 J

Explanation: Please find the attached files for the solution

4 0
4 years ago
Ppleaseeeeee anyone helpppp me :|||
jarptica [38.1K]

Answer:

i think c but im not sure

Explanation:

3 0
3 years ago
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