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nataly862011 [7]

3 years ago

5

suppose that a large cargo truck needs to cross a bridge. the truck is 30 m long and 3.2 m wide. the cargo exerts a force nof 54

,000 n. the bridge can only withstand 450 pa of pressure. is it safe for the truck to cross the bridge?

1 answer:

Tamiku [17]3 years ago

7 0

<span>No, because the truck applies more pressure than the bridge can support.</span>

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A capacitor consists of two closely spaced metal conductors of large area, separated by a thin insulating foil. It has an electr

Nata [24]

Answer:

- E = 11.55J

- Q = 0.17C

- E' = (1/4)E

Explanation:

- To calculate the amount of energy stored in the capacitor, you use the following formula:

$E=\frac{1}{2}CV^2$

C: capacitance = 3800.0*10^-6F

V: potential difference = 78.0V

$E=\frac{1}{2}(3800.0*10^{-6}C)(78.0V)^2=11.55J$

The energy stored in the capacitor is 11.55J

- If the electrical energy stored in the capacitor is 6.84J, the charge on the capacitor is:

$E=\frac{1}{2}QV\\\\Q=\frac{2E}{V}\\\\Q=\frac{2(6.84J)}{78.0V}=0.17C$

The charge on the capacitor is 0.17C

- If you take the capacitor as a parallel plate capacitor, you have that the energy stored on the capacitor is:

$E=\frac{1}{2}CV^2=\frac{1}{2}(\frac{\epsilon_oA}{d})V^2=\frac{1}{2}\frac{\epsilon_oAV^2}{d}\\\\$

A: area of the plates

d: distance between plates

If the distance between plates is increased by a factor of 4, you have:

$E'=\frac{1}{2}\frac{\epsilon_oAV^2}{(4d)}=\frac{1}{4}\frac{\epsilon_oAV^2}{2d}=\frac{1}{4}E$

Then, the stored energy in the capacitor is decreased by a a factor of (1/4)

6 0

3 years ago

HELPPPPPPP !!!!!! PLS A 0.050 kg Truck moving right at 0.20 m/s collides with a toy race car weighing 0.015 kg initially at rest

sergejj [24]

Answer:

$v_f=0.15\:\mathrm{m/s}$

Explanation:

From the Law of Conservation of Momentum, we can write the following equation:

$m_1v_1+m_2v_2=m_fv_f$

Because the toy car was initially at rest, $m_2v_2=0$ .

Therefore, we can plug in given values and solve for $v_f$ :

$m_1v_1=m_fv_f,\\0.050\cdot 0.20 = (0.050+0.015)v_f,\\v_f=\fbox{$0.15\:\mathrm{m/s}$}$ (two significant figures).

6 0

3 years ago

Can someone do this for the football

fiasKO [112]

G/292 cm
is the answer

7 0

3 years ago

Aluminium has a specific heat capacity of 900 J/(kg°C).

Ivanshal [37]

Answer:

24300000K

Explanation:

Q=mc(change in temperature)

900X2.0=1800.0

1800.0X13500= 24300K

4 0

3 years ago

A stone with a mass of 0.70 kg is attached to one end of a string 0.70 m long. The string will break if its tension exceeds 65.0

mixas84 [53]

Answer:v=8.06 m/s

Explanation:

Given

mass of stone $m=0.7 kg$

length of string $L=0.7 m$

Maximum Tension $T=65 N$

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$T=\frac{mv^2}{r}$

$65=\frac{0.7\times v^2}{0.7}$

$v^2=65$

$v=\sqrt{65}$

$v=8.06 m/s$

4 0

3 years ago