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sashaice [31]
3 years ago
13

A 4.1-kg ball is thrown from the top of a 4-m tall building (point A) with a speed of 1 m/s at an angle 2 degrees above the hori

zontal. If air resistance is negligible, what is the value of the kinetic energy of the ball as it hits the ground?
Physics
1 answer:
lubasha [3.4K]3 years ago
6 0

Answer:

K.E = 163 J

Explanation:

From the question we are told that:

Mass m=4.1kg

Height h=4m

Speed V=1m/s

Angle \theta= 2 \textdegree

Generally the equation for K.E is mathematically given by

Since

The potential energy and kinetic energy is equal to the kinetic energy as it hits the ground.

Therefore

 K.E=mgH + 0.5mV^2

 K.E = (4.1)(9.81)(4) + (4.1)(1)^2*0.5

 K.E = 163 J

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