Question

A 4.1-kg ball is thrown from the top of a 4-m tall building (point A) with a speed of 1 m/s at an angle 2 degrees above the horizontal. If air resistance is negligible, what is the value of the kinetic energy of the ball as it hits the ground?

Answer 1

Answer:

$K.E = 163 J$

Explanation:

From the question we are told that:

Mass $m=4.1kg$

Height $h=4m$

Speed $V=1m/s$

Angle $\theta= 2 \textdegree$

Generally the equation for K.E is mathematically given by

Since

The potential energy and kinetic energy is equal to the kinetic energy as it hits the ground.

Therefore

 $K.E=mgH + 0.5mV^2$

 $K.E = (4.1)(9.81)(4) + (4.1)(1)^2*0.5$

 $K.E = 163 J$