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4 years ago

What would happen to the earth without carbon dioxide

2 answers:

6 0

The Earth would become somewhat cooler, the oceans would become somewhat less acidic, and no trees or green plants could grow, so there could be no grazing animals or insects.

HACTEHA [7]4 years ago

3 0

The ability for CO2 to warm the surface of a planet through the absorption of infrared radiation is well known. What is much less appreciated, however, is just how effective of a gas it is in maintaining the greenhouse framework that helps to characterize the modern climate.

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In which item is energy stored in the form of gravitational potential energy? A. A slice of bread B. A compressed spring C. An a

marysya [2.9K]

The things that determine the amount of an object's gravitational potential energy are ...

-- mass of the object

-- gravitational acceleration in the place where the object is

-- height of the object above the ground or the floor

A). a slice of bread; No. It's still a slice of bread even if it's on the ground.

B. A compressed spring; No. It's still a compressed spring even if it's on the ground.

C. An apple on a tree; Yes ! It can't be an apple on a tree if it's on the ground.

D. A stretched bow string; No. It's still a stretched bowstring even if it's on the ground.

3 0

3 years ago

Read 2 more answers

Two identical charges, each -8.00 E-5 C, are separated by a distance of 20.0 cm (100 cm = 1 m). What is the force of repulsion?

Rom4ik [11]

F = 1440 N. The repulsion force between two identical charges, each -8.00x10⁻⁵C separated by a distance of 20.0 cm is 1440 N.

The easiest way to solve this problem is using Coulomb's Law given by the equation $F=k\frac{|q_{1}*q_{2}|}{r^{2} }$ , where k is the constant of proportionality or Coulomb's constant, q₁ and q₂ are the charges magnitude, and r is the distance between them.

We have to identical charges of -8.00x10⁻⁵C, are separated by a distance of 20.0 cm, and we need to know the force of repulsion between the charges.

First, we have to convert 20.0 cm to meters.

(20.0 cm x 1m)/100cm = 0.20 m

Using the Coulomb's Law equation:

$F = 9.00x10^{9}\frac{Nm^{2}}{C^{2}} \frac{|-8.00x10^{-5}C*-8.00x10^{-5}C|}{(0.20m)^{2} }$

$F = 9.00x10^{9}\frac{Nm^{2}}{C^{2}}(1.6x10^-7\frac{C^{2} }{m^{2} } })\\F = 1440N$

5 0

3 years ago

A non living factor in an ecosystem

I am Lyosha [343]

Answer:

Explanation:Abiotic is the answer.

8 0

3 years ago

A ball of mass 0.200kg with a velocity of 1.50i^m/s meets a ball of mass 0.300kg with a velocity of -0.400 i^ m/s in a head-on,

Monica [59]

Velocities of their center of mass after collisions are found by the following formula as shown in the image:

<h3>What are elastic collisions?</h3>

An elastic collision is one in which there is no energy lost during the impact. A moderately inelastic collision occurs when some energy is wasted yet the items do not cling together. The maximum amount of energy is wasted when the objects collide in a perfectly inelastic impact. The kinetic energy doesn't change.
It may be two dimensions or one dimension. Because there will always be some energy exchange, no matter how tiny, totally elastic collision is not conceivable in the real world.
While the overall system's linear momentum does not change, the individual momenta of the participating components do, and because these changes are equal and opposite in size and cancel each other out, the initial energy is conserved.

To learn more about Elastic collisions refer to:

brainly.com/question/2356330

#SPJ4

4 0

2 years ago

What is the charge of Scandium?

garik1379 [7]

+3 ....>>>>>>>>..... i have added 20 characters to properly explain my answer

:3

5 0

3 years ago

Read 2 more answers