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Colt1911 [192]
3 years ago
6

An object, initially at rest moves 250m in 17s. What is it's acceleration?

Physics
1 answer:
Gekata [30.6K]3 years ago
8 0
With the values you've given, only velocity can be found.
Acceleration is rate of change of velocity

d= 250s
t= 17s

a= d/t
 =\frac{250}{17}
 = 4.7 \frac{m}{s}
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A swimmer bounces almost straight up from a diving board and falls vertically feet first into a pool.she starts with a speed of
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Answer:

a) 1.20227 seconds

b) 0.98674 m

c) 7.3942875 m/s

Explanation:

t = Time taken

u = Initial velocity = 4.4 m/s

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

v=u+at\\\Rightarrow 0=4.4-9.81\times t\\\Rightarrow \frac{-4.4}{-9.81}=t\\\Rightarrow t=0.44852\ s

s=ut+\frac{1}{2}at^2\\\Rightarrow s=4.4\times 0.44852+\frac{1}{2}\times -9.81\times 0.44852^2\\\Rightarrow s=0.98674\ m

b) Her highest height above the board is 0.98674 m

Total height she would fall is 0.98674+1.8 = 2.78674 m

s=ut+\frac{1}{2}at^2\\\Rightarrow 2.78674=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{2.78674\times 2}{9.81}}\\\Rightarrow t=0.75375\ s

a) Her feet are in the air for 0.75375+0.44852 = 1.20227 seconds

v=u+at\\\Rightarrow v=0+9.81\times 0.75375\\\Rightarrow v=7.3942875\ m/s

c) Her velocity when her feet hit the water is 7.3942875 m/s

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Question 1 (1 point)
TiliK225 [7]

Answer:

The resultant velocity of the plane relative to the ground is;

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The direction of flight of the plane = North

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The direction of the wind = South

Therefore, representing the speed of the plane and the wind in vector format, we have;

The velocity vector of the plane = 210.\hat j

The velocity vector of the wind = -60.\hat j

Where, North is taken as the positive y or \hat j direction

The resultant velocity vector is found by summation of the two vectors as follows;

Resultant velocity vector = The velocity vector of the plane + The velocity vector of the wind

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The resultant velocity vector = 150.\hat j

Therefore, the resultant velocity of the plane relative to the ground = 150 kh/h north.

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