Answer:
Option C. C₃H₆O₃
Explanation:
From the question given above, the following data were obtained:
Empirical formula = CH₂O
Molecular mass = 90 g/mol
Molecular formula =?
The molecular formula of the compound can be obtained as follow:
Molecular formula = Empirical formula × n
Molecular formula = [CH₂O]ₙ
But
Molecular formula = molecular mass = 90
Therefore,
[CH₂O]ₙ = 90
Now, we shall determine the value of n in order to obtain the molecular formula of the compound.
[CH₂O]ₙ = 90
[12 + (2×1) + 16]n = 90
[12 + 2 + 16]n = 90
30n = 90
Divide both side by 30
n = 90/30
n = 3
Molecular formula = [CH₂O]ₙ
Molecular formula = [CH₂O]₃
Molecular formula = C₃H₆O₃
