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madreJ [45]
3 years ago
15

HELP PLZ!!!!!!!!!!!!!!

Physics
1 answer:
Sophie [7]3 years ago
7 0

Answer:

Since binary is only 1 and 0, you can use a flashlight to display something similar to Morse code (see explanation below)

Explanation:

In binary, 1 means "on" and 0 means "off". A way you can use visible light is through turning on and off a flashlight. If the flashlight is turned on, it would represent a 1. If the flashlight is turned off, it would represent a 0. To make the message easier and more accurately understood for the receiver make sure to flash the lights in a consistent pattern (ex. each flash lasts no longer than half a second, one second between each digit, etc.)

For example, let's say you're trying to send the message "11001"

  on     on    off     off     on

0       1       2       3       4       5      <em>Numbers represent seconds</em>

As you can see above the message starts at 0 seconds. Between 0 and 1 seconds the flashlight is turned on once. Between 1 and 2 seconds the flashlight is turned on again, Between 2 and 3 seconds as well as 3 and 4 seconds the flashlight is not turned on at all. And finally between 4 and 5 seconds the flashlight is turned on.

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How is newtons third law of motion demonstrated on a roller coaster?
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8 0
3 years ago
What are the primary colors? What are the secondary colors?
Jet001 [13]

Color Basics

Three Primary Colors (Ps): Red, Yellow, Blue.

Three Secondary Colors (S'): Orange, Green, Violet

5 0
3 years ago
Read 2 more answers
A powerful searchlight shines on a man. The man's cross-sectional area is 0.500m2 perpendicular to the light beam, and the inten
babymother [125]

Answer:

The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵N

(b) the force the light beam exerts is much too small to be felt by the man.

Explanation:

Given;

cross-sectional area of the man, A = 0.500m²

intensity of light, I = 35.5kW/m²

If all the incident light were absorbed, the pressure of the incident light on the man can be calculated as follows;

P = I/c

where;

P is the pressure of the incident light

I is the intensity of the incident light

c is the speed of light

P = \frac{I}{c} =\frac{35500}{3*10^8} = 1.18*10^{-4} \ N/m^2

F = PA

where;

F is the force of the incident light on the man

P is the pressure of the incident light on the man

A is the cross-sectional area of the man

F = 1.18 x 10⁻⁴ x 0.5 = 5.9 x 10⁻⁵ N

The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵ N

Therefore, the force the light beam exerts is much too small to be felt by the man.

8 0
4 years ago
What is the emf of a battery that increases the electric potential energy of 0.060 CC of charge by 0.70 JJ as it moves it from t
Evgen [1.6K]

Answer:

emf = 11.667 V

Explanation:

Given: charge q = 0.060 C, electric potential energy E =0.70 J,

Solution :

by definition 1 volt = 1 joule per coulomb

so Voltage = emf = E/C

emf =  0.70 J / 0.060 C

emf = 11.667 V

5 0
3 years ago
Read 2 more answers
Which material is LEAST dense?<br> zircon<br> oxygen<br> carbon disulfide<br> air
Natalija [7]

Answer:

Carbon disulfide soryy if im wrong\

Explanation:

7 0
3 years ago
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