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Marat540 [252]
3 years ago
13

Draw graph for positive acceleration, negative acceleration and zeo acceleration​

Physics
1 answer:
natulia [17]3 years ago
3 0

Answer:

Explanation:

horizontal is zero slope, and the vertical is undefined

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Light of wavelength 660 nm passes through two narrow slits 0.65 mm apart. The screen is 2.55 m away. A second source of unknown
stiv31 [10]

Answer:

Explanation:

Distance of 2 nd order fringe  x₁ = 2 λ D/d [ λ is wave length , D is distance of screen , d is slit distance.

x₁ = 2 x 660 x10⁻⁹x 2.55/.65 x 10⁻³.= 5.17846 x 10⁻³ m.

Distance of fringe for 2nd radiation = 5.178 x 10⁻³ -1.17 x 10⁻³ = 4.008 x10⁻³

4.008 x 10⁻³ = 2 x λ x 2.55/.65 x 10⁻³

λ = 511 nm approx.

 .

8 0
3 years ago
Over a period of more than 30 years, albert klein of california drove 2.5 × 106 km in one automobile. consider two charges, q1 =
Semenov [28]
For q3 to be in equilibrium the total force acting on it has to be zero.
Let's say that total distance traveled by car is L (this is just for the convenience).
We can set up a system of equations to find an answer. Let's say that from q1 to q3 the distance is r_1 and from q3 to q2 the distance is r_2, we know that this distance has to be equal to:
r_1+r_2=L km
The second equation is going to the total force acting on the charge q3:
F_{q3}=F_{q3q1}+F_{q3q2}=0\\ 0=k_c\frac{q_1q_3}{r_1^2}+k_c\frac{q_3q_2}{r^2}
k_c is the Coulomb's constant. Since left-hand side is zero we just divide whole equation with k_c to get rid of it:
0=\frac{q_1q_3}{r_1^2}+\frac{q_3q_2}{r^2}
Let's solve this for r_1^2:
0=\frac{8}{r_1^2}+\frac{24}{r^2}\\ \frac{1}{r_1^2}=-\frac{3}{r^2}\\ r_1^2=-\frac{r^2}{3};r_2=L-r_1\\ r_1^2=\frac{(L-r_1)^2}{3}\\ r_1^2=\frac{L^2-2Lr_1+r_1^2}{3}\\ 3r_1^2=L^2-2Lr_1+r_1^2\\ 2r_1^2+2Lr_1-L^2=0
Now we have a quadratic equation with following parameter:
a=2\\ b=2L\\ c=-L^2
We know that two solutions are:
r_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\ r_{1,\:2}=\frac{-2L\pm \sqrt{4L^2+8L^2}}{4}\\ r_{1,\:2}=\frac{-2L\pm \sqrt{12L^2}}{4}\\
We need a positive solution. When we plug in all the numbers we get:
r_1=0.915\cdot 10^6$km

6 0
3 years ago
A boiler is being used to heat water. The graph shows the temperature of
Vinvika [58]

Answer:

a. Liquid state

b. At point R. The physical state of water at its boiling point temperature of 100 degree Celsius will be both liquid state as well as gaseous state.

c. at 110 degrees it is in gaseous state

4 0
3 years ago
The main difference between speed and velocity involves
mars1129 [50]

Velocity is speed plus the direction of the speed.

6 0
3 years ago
Read 2 more answers
Pretend you're
vredina [299]

Answer

What type of phases?

4 0
3 years ago
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