If I set aside $5,000 in the bank to earn 6% annually, how much would I have after 5 years?

A grading scale is set up for 1000 students' test scores. It assumes the

astra-53 [7]

Answer:

464 students will score between 48 and 75. Using the z-distribution, we measure how many standard deviations each score is from the mean, then find the p-value associated with each score to find the proportion, and from the proportion, we find how many out of 1000.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

It assumes the scores are normally distributed with a mean score of 75 and a standard deviation of 15.

This means that $\mu = 75, \sigma = 15$

How many students will score between 48 and 75?

First we find the proportion, which is the pvalue of Z when X = 75 subtracted by the pvalue of Z when X = 48. So

X = 75

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{75 - 75}{15}$

$Z = 0$

$Z = 0$ has a p-value of 0.5

X = 48

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{48 - 75}{15}$

$Z = -1.8$

$Z = -1.8$ has a p-value of 0.0359

1 - 0.0359 = 0.4641

Out of 1000:

0.4641*1000 = 464

464 students will score between 48 and 75. Using the z-distribution, we measure how many standard deviations each score is from the mean, then find the p-value associated with each score to find the proportion, and from the proportion, we find how many out of 1000.

7 0

3 years ago

Which expression is equivalent to - (4-3)

LenaWriter [7]

This is equivalent to -1 ( 4 - 3 )
which simplified is -1
because 4-3 is 1 and 1 times -1 is -1

Hope this helps ;)

5 0

3 years ago

Read 2 more answers

Is 83,391,946 divisible by 4? YE or NO HELP ME PLZ T^T

Vanyuwa [196]

Answer:

No

Step-by-step explanation:

Reason for this is because when you divide 4 into 83,391,946 it ends up as 20847986.5 and since the number has to be whole its not divisible

4 0

2 years ago

Write the equation of a line in - form that contains the point (- 1, - 2) and is perpendicular to the line y = 5x - 10 degrees

galina1969 [7]

Answer:

y+2= -1/5(x+1)

Step-by-step explanation:

if lines are perpendicular their slopes are negative reciprocal

y=mx+b where m is the slope

y=5x-10 has the slope 5 so a perpendicular line will have slope -1/5

equation point slope form

(y-y1) = m(x-x1) where m is slope, and (x1,y1) any point that belongs to the line

y+2= -1/5(x+1)

3 0

2 years ago

A junk box in your room contains fourteen old batteries, seven of which are totally dead. You start picking batteries one at a

MrMuchimi

Answer:

A junk box in your room contains fourteen old batteries, seven of which are totally dead.

So, number of good batteries = $14-7=7$

a) The first two you choose are both good.

There is a 7/14 chance that we will pick a good battery.

Now there are 13 batteries left and out of that there are only 6 good ones remaining, so this becomes 6/13.

So, combined probability is = $\frac{7}{14}\times \frac{6}{13}$

= 0.23

b) At least one of the first three works.

$\frac{7}{14} \times \frac{6}{13} \times \frac{5}{12} =0.096$

And at least one is good battery, we get : $1-0.096=0.904$

c) The first four you pick all work.

There is a probability of 7/14 for the first one to work, 6/13 for the second, 5/12 for the third and 4/11 when the fourth is good, combined we get by multiplying all:

$\frac{7}{14}\times \frac{6}{13}\times \frac{5}{12}\times \frac{4}{11}=0.0344$

d) You have to pick five batteries to find one that works.

This condition means that we pick 4 bad batteries and 1 good battery.

The probability of picking 4 bad batteries is -

$\frac{7}{14}\times \frac{6}{13}\times \frac{5}{12}\times \frac{4}{11}=0.0344$

Since there are 7 good batteries remaining in 10 batteries so we will multiply 7/10 in 0.0344 to know the fifth one that finally works.

This becomes = $0.0344\times0.7=0.024$

5 0

3 years ago