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kaheart [24]
3 years ago
8

In science class, Harry and his classmates are performing a controlled scientific investigation. The teacher has already picked

a topic and testable question for the class to study and has provided background research on the topic.
Before performing the investigation, the students must first
A.
form a hypothesis to predict the outcome of the investigation.
B.
analyze the data that results from the investigation.
C.
record data from the investigation in graphs and charts.
D.
communicate the results of the investigation with the teacher.
Chemistry
2 answers:
Snowcat [4.5K]3 years ago
6 0

A is the correct answer

miv72 [106K]3 years ago
4 0

The steps of research follow the sequence as

a) make an observation

b) Propose a hypothesis for the observation made

c) Prediction of the correctness of hypothesis

d) Perform experiment

e) conclude the problem

So answer is

i) record data from the investigation in graphs and charts.

ii) form a hypothesis to predict the outcome of the investigation.

iii) analyze the data that results from the investigation

iv) communicate the results of the investigation with the teacher.



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Calculate the number of moles in 7.41 X 1017 atoms Ag.
jolli1 [7]

Answer:

1.23x10^-6 mole

Explanation:

A clear understanding of Avogadro's hypothesis proved that 1mole of any substance contains 6.02x10^23 atoms. This indicates that 1mole of Ag contains 6.02x10^23 atoms.

Now, 1f 1mole of Ag contains 6.02x10^23 atoms, then Xmol of Ag will contain 7.41x10^17 atoms i.e

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4 0
3 years ago
The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calculate the volume of CO2 genera
nevsk [136]

Answer:

The volume of carbon dioxide gas generated 468 mL.

Explanation:

The percent by mass of bicarbonate in a certain Alka-Seltzer = 32.5%

Mass of tablet = 3.45 g

Mass of bicarbonate =3.45 g\times \frac{32.5}{100}=1.121 mol

Moles of bicarbonate ion = \frac{1.121 g/mol}{61 g/mol}=0.01840 mol

HCO_3^{-}(aq)+HCl(aq)\rightarrow H_2O(l)+CO_2(g)+Cl^-(aq)

According to reaction, 1 mole of bicarbonate ion gives with 1 mole of carbon dioxide gas , then 0.01840 mole of bicarbonate ion will give:

\frac{1}{1}\times 0.01840 mol=0.01840 mol of carbon dioxide gas

Moles of carbon dioxide gas  n = 0.01840 mol

Pressure of the carbon dioxide gas = P = 1.00 atm

Temperature of the carbon dioxide gas = T = 37°C = 37+273 K=310 K

Volume of the carbon dioxide gas = V

PV=nRT (ideal gas equation)

V=\frac{nRT}{P}=\frac{0.01840 mol\times 0.0821 atm L/mol K\times 310 K}{1.00 atm}=0.468 L

1 L = 1000 mL

0.468 L =0.468 × 1000 mL = 468 mL

The volume of carbon dioxide gas generated 468 mL.

5 0
3 years ago
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