Gay Lussac's Law
Convert:
200°C = 200 + 273 = 473 K
50°C = 50 + 273 = 323 K
Input the value:
Answer:
0.1113 mol
Explanation:
Data Given:
no. of atoms of CH₄= 6.70 x 10²² atoms
no. of moles of methane (CH₄) = ?
Solution:
we will find no. of moles of methane (CH₄)
Formula used
no. of moles = no. of atoms / Avogadro's number
Where
Avogadro's number = 6.022 x 10²³
Put values in above equation
no. of moles = 6.70 x 10²² atoms / 6.022 x 10²³ (atoms/mol)
no. of moles = 0.1113 mol
So,
There are 0.1113 moles of methane.
Answer:
- 278.85 J
Explanation:
Given that:
Pressure = 1.1 atm
The initial volume V₁ = 0.0 L
The final volume V₂ = 2.5 L
The work that takes place in a reaction at constant pressure can be expressed by using the equation:
W = P(V₂ - V₁ )
Since the volume of the gas is expanded from 0 to 2.5 L when 1.1 atm pressure is applied. Then, the work can be given by the expression:
W = - P(V₂ - V₁ )
W = -1.1 atm ( 2.5 - 0.0) L
W = -1.1 atm (2.5 L)
W = -2.75 atm L
Recall that:
1 atm L = 101.4 J
Therefore;
-2.75 atm L = ( -2.75 × 101.4 )J
= -278.85 J
Thus, the work required at the chemical reaction when the pressure applied is 1.1 atm = - 278.85 J
Answer:
Option B is correct = 1,3
Explanation:
Chemical equation:
C₂H₄ + O₂ → CO₂ + H₂O
Balanced chemical equation:
C₂H₄ + 3O₂ → 2CO₂ + 2H₂O
Step 1:
Left side Right side
C = 2 C = 1
H = 4 O = 3
O = 2 H = 2
Step 2:
C₂H₄ + O₂ → 2CO₂ + H₂O
Left side Right side
C = 2 C = 2
H = 4 O = 5
O = 2 H = 2
Step 3:
C₂H₄ + O₂ → 2CO₂ + 2H₂O
Left side Right side
C = 2 C = 2
H = 4 O = 6
O = 2 H = 4
Step 4:
C₂H₄ + 3O₂ → 2CO₂ + 2H₂O
Left side Right side
C = 2 C = 2
H = 4 O = 6
O = 6 H = 4
