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kotykmax [81]
3 years ago
11

How many grams are in 2.38 moles of AlCl₃? please

Chemistry
1 answer:
marshall27 [118]3 years ago
5 0
You can view more details on each measurement unit: molecular weight of AlCl3 or grams This compound is also known as Aluminium Chloride. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles AlCl3, or 133.340538 grams.

Hope it helps
Please mark brainliest
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A garbage collector collects food wrappers and aluminum cans from a park. What type of waste is the garbage collector collecting
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Your answer to this question would be B. packaging waste.

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3 0
3 years ago
Read 2 more answers
Why does Beryllium have a larger first Ionization energy than boron?
Nata [24]
This is an exception to the general electronegativity trend. It can be explained by looking at the electron configurations of both elements.

<span>Be:[He]2<span>s2
</span></span><span>B:[He]2<span>s2</span>2<span>p1

</span></span>

When you remove an electron from beryllium, you are taking away an electron from the 2s orbital. When you remove an electron from boron, you are taking an electron from the 2p orbital. The 2p electrons have more energy than the 2s, so it is easier to remove them as they can more strongly resist the effective nuclear charge of the nucleus.

7 0
3 years ago
Metals (M) in group 2 of the periodic table form ionic bonds
egoroff_w [7]

Answer:

16

Explanation:

Group two elements are alkaline earth metal.

All these have two valance electrons. In order to achieve noble gas configuration it loses its two valance and get complete octet.

Reaction with group 16.

Reaction with oxygen,

They react with oxygen and form oxide.

2Ba   +   O₂   →    2BaO

2Mg  +   O₂   →    2MgO

2Ca +   O₂   →    2CaO

this oxide form hydroxide when react with water,

BaO  + H₂O   →  Ba(OH)₂

MgO  + H₂O   →  Mg(OH)₂

CaO  + H₂O   →  Ca(OH)₂

With sulfur,

Mg + S   →  MgS

Ca + S   →  CaS

Ba + S   →  BaS

5 0
3 years ago
What mass of NaC6H5COO should be added to 1.5 L of 0.40 M C6H5COOH solution at 25 °C to produce a solution with a pH of 3.87 giv
statuscvo [17]

Answer:

41 g

Explanation:

We have a buffer formed by a weak acid (C₆H₅COOH) and its conjugate base (C₆H₅COO⁻ coming from NaC₆H₅COO). We can find the concentration of C₆H₅COO⁻ (and therefore of NaC₆H₅COO) using the Henderson-Hasselbach equation.

pH = pKa + log [C₆H₅COO⁻]/[C₆H₅COOH]

pH - pKa = log [C₆H₅COO⁻] - log [C₆H₅COOH]

log [C₆H₅COO⁻] = pH - pKa + log [C₆H₅COOH]

log [C₆H₅COO⁻] = 3.87 - (-log 6.5 × 10⁻⁵) + log 0.40

[C₆H₅COO⁻] = [NaC₆H₅COO] = 0.19 M

We can find the mass of NaC₆H₅COO using the following expression.

M = mass NaC₆H₅COO / molar mass NaC₆H₅COO × liters of solution

mass NaC₆H₅COO = M × molar mass NaC₆H₅COO × liters of solution

mass NaC₆H₅COO = 0.19 mol/L × 144.1032 g/mol × 1.5 L

mass NaC₆H₅COO = 41 g

7 0
3 years ago
7. The youngest part of the ocean floor is found ____.
aev [14]

Answer:

The answer is Near The Ocean Ridges.

5 0
3 years ago
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