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Oliga [24]
3 years ago
5

PLEASE HELP WILL GIVE BRAINLEST

Chemistry
1 answer:
aliina [53]3 years ago
8 0

Answer:

Option A.

Lower air pressure results in a lower boiling point

Explanation:

This is because in an open system, the lower the pressure the lesser the energy that will be required for boiling point. The is little or no collision of air molecules with the surface of the liquid

But if there is increase in pressure, more energy will be required to get to boiling point because there will be strong collision between air molecules and surface of the liquid.

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What volume of 12 M NaOH and 2 M NaOH should be mixed to get 2 litres of 9 M NaOH solution?
Sergio [31]
8/5lit.. of 12M NaOH
2/5lit.. of 2M NaOH
7 0
3 years ago
Find the pH of a solution that has an H+ concentration of 2.5x10-3 M
Nastasia [14]

Answer:

The pH is 2, 60

Explanation:

The pH gives us an idea of the acidity or basicity of a solution. It is calculated as:

pH = -log (H +)= -log (2.5x10-3 )

<em>pH=2, 60</em>

7 0
2 years ago
The concentration of a solution can be expressed in
puteri [66]
The concentration of a solution can be expressed in (4) <span>moles per liter~</span>
3 0
2 years ago
Read 2 more answers
What is the molar concentration of 35 mL of H2SO4 that neutralizes 25 mL of 0.320M NaOH
stira [4]
V ( H2SO4) = 35 mL / 1000 => 0.035 L

M ( H2SO4) = ?

V ( NaOH ) = 25 mL / 1000 => 0.025 L 

M ( NaOH ) = 0.320 M

number of moles NaOH:

n = M x V

n = 0.025 x 0.320 => 0.008 moles of NaOH

Mole ratio:

<span>2 NaOH + H2SO4 = Na2SO4 + 2 H2O
</span>
2 moles NaOH ---------------------- 1 mole H2SO4
0.008 moles moles NaOH ---------- ??

0.008 x 1 / 2 => 0.004 moles of H2SO4 :

Therefore:

M ( H2SO4) = n / V

M = 0.004 /  0.035

= 0.114 M

hope this helps!



6 0
3 years ago
If the products of a reaction are Co2 and 2H20, what is known about the<br>reactants?​
Svetradugi [14.3K]

Answer:

Reactant : A combustion of hydrocarbon.

Explanation:

It is known that when hydrocarbons are involved in combustion, they produce carbon dioxide and water.

CxHy + (x+y/4)O2 ===> xCO2 + y/2H2O

4 0
2 years ago
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