Which happens when a reversible reaction reaches a state of chemical equilibrium?

Chemistry

2 answers:

Trava [24]3 years ago

5 0

Explanation:

Reversible reactions that happen in a closed system eventually reach equilibrium. At equilibrium, the concentrations of reactants and products do not change. But the forward and reverse reactions have not stopped - they are still going on, and at the same rate as each other.

Marta_Voda [28]3 years ago

3 0

Answer:

The Rate of forward and reverse reactions are equal

Explanation:

This is the correct the answer!

Have a great day!

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Carbon is the main constituent of hydrocarbons. Why some are called unsaturated hydrocarbon? Briefly describe.

maw [93]

Some hydrocarbons are regarded as unsaturated because they contain double or triple bonds between adjacent carbon atoms.

<h3>What are hydrocarbons?</h3>

Hydrocarbons are any organic compounds that contain hydrogen and carbon in its structure.

Hydrocarbons can be grouped into the following based on whether they contain single or double bonds:

Saturated hydrocarbons - contain only single bonds e.g. alkanes
Unsaturated hydrocarbons - contain double and triple bonds e.g. alkenes

Therefore, it can be said that some hydrocarbons are regarded as unsaturated because they contain double or triple bonds between adjacent carbon atoms.

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2 years ago

What mass of butane in grams is necessary to produce 1.5×103 kj of heat what mass of co2 is produced?

kari74 [83]

The heat of reaction (i.e. combustion) of butane ( $C_{4} H_{10}$ ) when reacted with oxygen ( $O_{2}$ )  is -2658 kJ/mol butane, and the chemical reaction is given by:

$C_{4} H_{10}$ + $\frac{13}{2} O_{2}$ ---> $4 CO_{2}$ + $5 H_{2}O$

The mass of butane required in the reaction is based on the heat produced by the reaction, which is given to be -1,500 kJ. The minus sign is added because the reaction releases heat (exothermic), which means that the products are in a "lower energy state" than the reactants.

Dividing this with the heat of reaction per mole of butane reacted would give the number of moles butane required. Then, multiplying the answer with the molar mass of butane which is 58 grams/mole, will give the mass of butane required.

Moles of butane = [(-1,500 kJ)/(-2658 kJ/mol butane)]
Moles of butane = 0.5643 moles butane

Mass of butane  = 0.5643 moles butane * 58 grams/mol butane
Mass of butane = 32.73 grams butane

The mass of carbon dioxide ( $CO_{2}$ ) can be determined by multiplying the moles of butane ( $C_{4} H_{10}$ ) with the mole ratio of ( $CO_{2}$ ) produced to the ( $C_{4} H_{10}$ ) reacted, and then with the molar mass of ( $CO_{2}$ ), which is 44 grams/mole.

Mass of carbon dioxide produced
= 0.5643 moles butane * [4 moles $CO_{2}$ / 1 mole $C_{4} H_{10}$ ] * 44 grams/mole $CO_{2}$

Mass of carbon dioxide produced
= 99.32 grams $CO_{2}$

Thus, the mass of butane required is 32.73 grams, and the mass of carbon dioxide produced from the reaction of this amount of butane is 99.32 grams.

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3 years ago

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