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Travka [436]
3 years ago
5

Which happens when a reversible reaction reaches a state of chemical equilibrium?

Chemistry
2 answers:
Trava [24]3 years ago
5 0

Explanation:

Reversible reactions that happen in a closed system eventually reach equilibrium. At equilibrium, the concentrations of reactants and products do not change. But the forward and reverse reactions have not stopped - they are still going on, and at the same rate as each other.

Marta_Voda [28]3 years ago
3 0

Answer:

The Rate of forward and reverse reactions are equal

Explanation:

This is the correct the answer!

Have a great day!

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Answer:

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Explanation:

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2 years ago
Round off the following numbers to the number of significant figures (sf) indicated.
Flura [38]

Answer:

a. 7.52

b. 16.5

c. 85

d. 6.03

Explanation:

significant number exempts 0 as a number which explains the last one. The two significant numbers there are 6 and 3

6 0
3 years ago
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.500 mol of br2 and .500 mol of cl2 are placed in a .500L flask and allowed to reach equilibrium. at equilibrium the flask was f
Tasya [4]

Answer : The value of K_c for the given reaction is, 0.36

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

The given equilibrium reaction is,

Br_2(aq)+Cl_2(aq)\rightleftharpoons 2BrCl(aq)

The expression of K_c will be,

K_c=\frac{[BrCl]^2}{[Br_2][Cl_2]}

First we have to calculate the concentration of Br_2,Cl_2\text{ and }BrCl.

\text{Concentration of }Br_2=\frac{Moles}{Volume}=\frac{0.500mol}{0.500L}=1M

\text{Concentration of }Cl_2=\frac{Moles}{Volume}=\frac{0.500mol}{0.500L}=1M

\text{Concentration of }BrCl=\frac{Moles}{Volume}=\frac{0.300mol}{0.500L}=0.6M

Now we have to calculate the value of K_c for the given reaction.

K_c=\frac{[BrCl]^2}{[Br_2][Cl_2]}

K_c=\frac{(0.6)^2}{(1)\times (1)}

K_c=0.36

Therefore, the value of K_c for the given reaction is, 0.36

6 0
3 years ago
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What happens to the solar energy absorbed by plants during photosynthesis ?
zzz [600]

Answer:

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Explanation:

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3 years ago
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Balance equation Al(s)+__CuSO4(aq) = ____Al2(SO4)3(aq)+____Cu(s)
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