The ship sails at 20 km / h.
So
20 km / h x 2 h = 40 km
The boat moves 40 km to the northeast.
Then, in the same way:
20 km / h x 1 h = 20 km.
The ship moves 20 km northwest.
We solve this problem using vectors. In this case, we must perform the sum of two vectors a and b
a) magnitude = 40 km and direction 20 degrees east
b) magnitude = 20 km and direction 10 degrees northwest
In Cartesian coordinates, these vectors are written as:
a) 40sin (20º) i + 40cos (20º) j = 13,68i + 37,59j
b) -20sin (10th) i + 20cos (10th) j = -3,473i + 19,70j
The displacement vector of the ship would be the sum of a + b
a + b = 10,207i + 57,29j Finally, the magnitude of the a + b vector will tell us how far the ship is
√(10.21² + 57.29²) = 58.92km
The answer is -12.
All you have to do is substitute the variables for their values and solve.
Hope this helps!
Answer:
55135 lbs (rounded to the nearest pound)
Step-by-step explanation:
diameter of tank = 15 ft
Radius = 15/2 =7.5
volume of hemisphere = 2/3 ×π× 7.5³=883.5729
total weight of water = 62.4 × 883.57 = 55134.768
55134.768 rounded to the nearest pound is 55135 lb
♥ Hope this helped ♥
It is 60% because 18/30=0.6
