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Delicious77 [7]
3 years ago
11

What is the product of the unbalanced combustion reaction below?

Chemistry
1 answer:
bezimeni [28]3 years ago
7 0

Answer:

C

Explanation:

because it is complete combustion so it will produced CO2 +H2O :)

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If it is 9 am in San Francisco, is it also 9 am in New York? Why or why not?
lys-0071 [83]

Answer:

san franciso is 3 hours beind and with NewYork

Explanation:

5 0
2 years ago
Read 2 more answers
Calculate the mass of h2o and c6 h12 o6 required to make 250 gram of 40% solution of glucose
Sedaia [141]
40% solution of glucose is where the solution contains, by weight, 40% glucose and 60% water. 

Therefore, if the total weight of the solution is 250 g, 
mass of the glucose (C6H12O6) = 250 g * 40% = 100 g
mass of water (H2O) = 250 g * 60% = 150 g

Mass of water can also be calculated by subtracting the weight of glucose from the total weight of the solution:
mass of water = 250g-100g = 150g.
5 0
3 years ago
What salt is produced in each of the following neutralization reactions? HNO3(aq)+KOH(aq)→H2O(l)+? HNO3(aq)+Ca(OH)2(aq)→H2O(l)+?
Igoryamba

Answer:

1. KNO3

2. Ca(NO3)2

3. CaCl2

4. KCl

Explanation:

In each of the neutralization reactions, the H from one of the reactant(acid) will combine with the OH from the other reactant (base) to form water while the other elements combine to give the salt as shown below:

1. HNO3 + KOH → H2O + KNO3

The salt produced is KNO3

2. 2HNO3 + Ca(OH)2 → 2H2O + Ca(NO3)2

The salt produced is Ca(NO3)2

3. 2HCl +Ca(OH)2 → 2H2O + CaCl2

The salt produced is CaCl2

4. HCl +KOH → H2O + KCl

The salt produced is KCl

5 0
3 years ago
Explain how are elements classified and provide an example
swat32
By nonmetals, metals, and gases
4 0
3 years ago
Noble gas configuration
saw5 [17]

Answer:

Rubidium= [Kr] 5s^1

Calcium= [Ar] 4s^2

Aluminium= [Ne] 3s^2 3p^1

Explanation:

A noble gas configuration begins with the elemental symbol of the last noble gas prior to the atom. The symbol is then followed by the remaining electrons.

Hope this helped! good luck :)

3 0
3 years ago
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