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snow_lady [41]
4 years ago
15

What is an experimental control

Chemistry
1 answer:
attashe74 [19]4 years ago
3 0

The experimental control is the standard used as a comparison for the experimental groups.


For example, you may be trying to find out how different types of disinfectants affect bacterial growth.  The control group would receive <em>no</em> disinfectant whereas the experimental groups would be the ones on which the disinfectants were tested.


Hope this makes sense!

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What function does residual CO2 serve
Luba_88 [7]

The function does residual Co2 plays big part and in maintaining the body’s homeostasis. The addition of respiratory to reserve volume or residual volume.  The lung is the one that who protect the organs, so in exchange of oxygen and carbon dioxide.

6 0
3 years ago
Which of the following elements would be the most reactive?
Aleksandr-060686 [28]
I think it's Chlorine but, not 100% sure. so C.
7 0
3 years ago
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Which equation is used to help form the combined gas law? mc009-1. Jpg mc009-2. Jpg mc009-3. Jpg mc009-4. Jpg.
Luba_88 [7]

The combined gas law equation has been \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}.

The combined gas law has been assigned to the ideal gas. It has been stating that ideal gas are having negligible inter-molecular attraction and collision resulting in the absence of pressure and volume from the particles.

In an ideal gas the equation has been given as:

PV=nRT

Where, <em>P </em>has been the pressure of the gas

<em>V </em>has been the volume of the gas

<em>n </em>has been the moles of the gas

<em>R </em>has been a constant

<em>T </em>has been the temperature of the gas

The combined gas law has been given as the change in the pressure, and volume for a gas. It has been given as:

\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}

For more information about combined gas law, refer to the link:

brainly.com/question/13154969

7 0
3 years ago
Foxplain the term hybridizatim​
serg [7]

Answer:

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In chemistry, orbital hybridisation (or hybridization) is the concept of mixing atomic orbitals into new hybrid orbitals (with different energies, shapes, etc., than the component atomic orbitals) suitable for the pairing of electrons to form chemical bonds in valence bond theory.

Explanation:

6 0
3 years ago
2Mg + O2 → 2MgO<br><br> If you are burning 5.8332 g of Mg, how many grams of MgO will this make?
LekaFEV [45]
<h3>Answer:</h3>

9.6724 g MgO

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Stoichiometry</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2Mg + O₂ → 2MgO

[Given] 5.8332 g Mg

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol Mg = 2 mol MgO

Molar Mass of Mg - 24.31 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of MgO - 24.31 + 16.00 = 40.31 g/mol

<u>Step 3: Stoichiometry</u>

  1. Set up:                              \displaystyle 5.8332 \ g \ Mg(\frac{1 \ mol \ Mg}{24.31 \ g \ Mg})(\frac{2 \ mol \ MgO}{2 \ mol \ Mg})(\frac{40.31 \ g \ MgO}{1 \ mol \ MgO})
  2. Multiply/Divide:                                                                                               \displaystyle 9.67241 \ g \ MgO

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 5 sig figs.</em>

9.67241 g MgO ≈ 9.6724 g MgO

5 0
3 years ago
Read 2 more answers
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