The function does residual Co2 plays big part and in
maintaining the body’s homeostasis. The addition of respiratory to reserve
volume or residual volume. The lung is
the one that who protect the organs, so in exchange of oxygen and carbon
dioxide.
I think it's Chlorine but, not 100% sure. so C.
The combined gas law equation has been
.
The combined gas law has been assigned to the ideal gas. It has been stating that ideal gas are having negligible inter-molecular attraction and collision resulting in the absence of pressure and volume from the particles.
In an ideal gas the equation has been given as:

Where, <em>P </em>has been the pressure of the gas
<em>V </em>has been the volume of the gas
<em>n </em>has been the moles of the gas
<em>R </em>has been a constant
<em>T </em>has been the temperature of the gas
The combined gas law has been given as the change in the pressure, and volume for a gas. It has been given as:

For more information about combined gas law, refer to the link:
brainly.com/question/13154969
Answer:
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In chemistry, orbital hybridisation (or hybridization) is the concept of mixing atomic orbitals into new hybrid orbitals (with different energies, shapes, etc., than the component atomic orbitals) suitable for the pairing of electrons to form chemical bonds in valence bond theory.
Explanation:
<h3>
Answer:</h3>
9.6724 g MgO
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Stoichiometry</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN - Balanced] 2Mg + O₂ → 2MgO
[Given] 5.8332 g Mg
<u>Step 2: Identify Conversions</u>
[RxN] 2 mol Mg = 2 mol MgO
Molar Mass of Mg - 24.31 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of MgO - 24.31 + 16.00 = 40.31 g/mol
<u>Step 3: Stoichiometry</u>
- Set up:

- Multiply/Divide:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 5 sig figs.</em>
9.67241 g MgO ≈ 9.6724 g MgO