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3 years ago

What is an experimental control

Chemistry

1 answer:

attashe74 [19]3 years ago

3 0

The experimental control is the standard used as a comparison for the experimental groups.

For example, you may be trying to find out how different types of disinfectants affect bacterial growth. The control group would receive no disinfectant whereas the experimental groups would be the ones on which the disinfectants were tested.

Hope this makes sense!

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a certain compound was found to contain 54.0 g of carbon and 10.5 grams of hydrogen. its relative molecular mass is 86.0. find t

dexar [7]

Answer:

empirical formula = C3H7

molecular formula = C6H14

3 0

3 years ago

The reaction C4H8(g)⟶2C2H4(g) C4H8(g)⟶2C2H4(g) has an activation energy of 262 kJ/mol.262 kJ/mol. At 600.0 K,600.0 K, the rate c

crimeas [40]

Answer : The rate constant at 785.0 K is, $1.45\times 10^{-2}s^{-1}$

Explanation :

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

or,

$\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_1$ = rate constant at $600.0K$ = $6.1\times 10^{-8}s^{-1}$

$K_2$ = rate constant at $785.0K$ = ?

$Ea$ = activation energy for the reaction = 262 kJ/mole = 262000 J/mole

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = $600.0K$

$T_2$ = final temperature = $785.0K$

Now put all the given values in this formula, we get:

$\log (\frac{K_2}{6.1\times 10^{-8}s^{-1}})=\frac{262000J/mole}{2.303\times 8.314J/mole.K}[\frac{1}{600.0K}-\frac{1}{785.0K}]$

$K_2=1.45\times 10^{-2}s^{-1}$

Therefore, the rate constant at 785.0 K is, $1.45\times 10^{-2}s^{-1}$

7 0

3 years ago

Why do Hurricanes not form directly on the equator?

Gemiola [76]

They do form directly on the equators

8 0

3 years ago

Why are alkali metals so reactive?

Savatey [412]

Answer:

Alkali metals are among the most reactive metals. This is due in part to their larger atomic radii and low ionization energies. They tend to donate their electrons in reactions and have an oxidation state of +1. ... All these characteristics can be attributed to these elements' large atomic radii and weak metallic bonding.

Explanation:

I hope it will help you.....

#CARRYONLERANING

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2 years ago

What is the weight of oxygen in 50gwater

8_murik_8 [283]

To compute the required mass of the element to form the given molecules, we'll use the general formula shown below:

{eq}\displaystyle m_1=\frac{M_1}{M_2}\times m_2 {/eq}, where,

{eq}M_1 {/eq} is the molecular weight of the element.

{eq}M_2 {/eq} is the molecular weight of the given molecule.

{eq}m_2 {/eq} is the mass of the given molecule.

Answer and Explanation:

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The given value is:

The value of the mass of the water molecule is {eq}m_2=\rm 50\ grams {/eq}.

The chemical reaction for the formation of water...

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Formula for Mass: Definition & Examples

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Chapter 28 / Lesson 42

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What is mass? Learn the mass definition and how to find the mass of an object using the mass formula. See common mass characteristics and properties.