Question

Select all the correct answers.

Answer 1

Answer:

C2H5OH

Explanation:

To know the compound used as the sample, let us calculate the empirical formula for the compound. This is illustrated below:

Data obtained from the question include:

Carbon (C) = 52.14%

Hydrogen (H) = 13.13%

Oxygen (O) = 34.73%

Next, divide the above by their individual molar mass

C = 52.14/12 = 4.345

H = 13.13/1 = 13.13

O = 34.73/16 = 2.171

Next, divide the above by the smallest number.

C = 4.345/2.171 = 2

H = 13.13/2.171 = 6

O = 2.171/2.171 = 1

Therefore, empirical formula for the compound is C2H6O

Now we can re-arrage C2H6O to become C2H5OH.

Therefore, the compound used as the sample is C2H5OH