Answer:
C2H5OH
Explanation:
To know the compound used as the sample, let us calculate the empirical formula for the compound. This is illustrated below:
Data obtained from the question include:
Carbon (C) = 52.14%
Hydrogen (H) = 13.13%
Oxygen (O) = 34.73%
Next, divide the above by their individual molar mass
C = 52.14/12 = 4.345
H = 13.13/1 = 13.13
O = 34.73/16 = 2.171
Next, divide the above by the smallest number.
C = 4.345/2.171 = 2
H = 13.13/2.171 = 6
O = 2.171/2.171 = 1
Therefore, empirical formula for the compound is C2H6O
Now we can re-arrage C2H6O to become C2H5OH.
Therefore, the compound used as the sample is C2H5OH
