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Dmitry_Shevchenko [17]
3 years ago
9

In an elastic collision, ________. A. an individual molecule in the collision never loses energy B. the molecules involved in th

e collision move in a circular motion C. the total energy of all molecules in the collision remains constant D. the molecules involved in the collision are held to each other by strong intermolecular interactions
Physics
1 answer:
Aleks04 [339]3 years ago
3 0

Answer:

Im pretty sure its B im very sorry if its wrong.

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If the pressure above a solution containing a gas solute is reduced, the limit of the gas's solubility will decrease.
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As the mass of an object increases so does its gravitational force. <br> a. True <br> b. False
vichka [17]

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False

Explanation:

Gravity force is constant.

There some places on Earth that gravity has a variation, but in general, it is the same everywhere.

If you analyze the equation for the weight, which is the action of the gravity to mass, you'll see that W=mg, where m is the mass and g, is gravity.

If you increase the mass, what you are increasing is weight and not gravity.

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3 years ago
What does the diagram represent?
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3 years ago
You shake a bottle of soda and take off the cap. If the soda shoots out of the
Harman [31]

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A. 16.9 m

Explanation:

I think this is the answer i am not sure

but hope it helps

3 0
3 years ago
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At t=0 bullet A is fired vertically with an initial (muzzle) velocity of 450 m/s. When 3s. bullet B is fired upward with a muzzl
Debora [2.8K]

Answer:

At time 10.28 s after A is fired bullet B passes A.

Passing of B occurs at 4108.31 height.

Explanation:

Let h be the height at which this occurs and t be the time after second bullet fires.

Distance traveled by first bullet can be calculated using equation of motion

s=ut+0.5at^2 \\

Here s = h,u = 450m/s a = -g and t = t+3

Substituting

h=450(t+3)-0.5\times 9.81\times (t+3)^2=450t+1350-4.9t^2-29.4t-44.1\\\\h=420.6t-4.9t^2+1305.9

Distance traveled by second bullet

Here s = h,u = 600m/s a = -g and t = t

Substituting

h=600t-0.5\times 9.81\times t^2=600t-4.9t^2\\\\h=600t-4.9t^2 \\

Solving both equations

600t-4.9t^2=420.6t-4.9t^2+1305.9\\\\179.4t=1305.9\\\\t=7.28s \\

So at time 10.28 s after A is fired bullet B passes A.

Height at t = 7.28 s

h=600\times 7.28-4.9\times 7.28^2\\\\h=4108.31m \\

Passing of B occurs at 4108.31 height.

6 0
3 years ago
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