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harkovskaia [24]
3 years ago
6

Газ имеет объем 2 м³ при давлении 10° Па. Найдите обьем этого газа при изотермическом уменьшении давления в два раза.​

Physics
1 answer:
slamgirl [31]3 years ago
7 0

Answer:

sorry i didn't understand

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A guy wire helping to stabilize a transmitting tower 500 m high makes in angle of 50° with the ground. In a strong wind, the tow
timurjin [86]

They give us the cable tension t = 1500 newton. We assume that the mass of the cable is negligible compared to that of the tower.

We have a force t of 1500 Newton. This force has a vertical component on the y axis and a horizontal component on the x axis.

Of these two components of force, we are especially interested in calculating is the magnitude of the vertical component.

If the angle that it forms with the ground is 50 °, then the vertical component of the force is:

Fy = 1500sin (50)

Fy = 1149 N. <1200 N

The wire will not be loose

6 0
3 years ago
If the electric potential in a region is given by v(x)=7/x2 the x component of the electric field in that region is
lions [1.4K]

Hi there!

Recall that:
\Delta V = -\int\limits^a_b {E \cdot } \, dx

Given an electric field, the potential difference can be solved by using integration. Similarly:
E = -\frac{dV}{dx}

We can differentiate the electric potential equation to solve for the electric field.

Use the power rule:
\frac{dy}{dx} x^n = nx^{n - 1}

Differentiate the given equation.

-\frac{dV}{dx}\frac{7}{x^2} =- \frac{dV}{dx}7x^{-2} = -(-14x^{-3}) = \frac{14}{x^3}

Or:
\boxed{E(x) = \frac{14}{x^3}}

6 0
2 years ago
What is the magnification of an astronomical telescope whose objective lens has a focal length of 71 cm and whose eyepiece has a
Rus_ich [418]

To solve this problem it is necessary to apply the concepts related to optical magnification (is the process of enlarging the apparent size, not physical size, of something.). Specifically the angular magnification of an optical telescope is given by

M = -\frac{f_o}{f_e}

Where,

f_o = Focal length of the objective lens in a refractor

f_e = Focal length of the eyepiece

Our values are given as

f_o = 71cm

f_e =  2.1cm

Replacing we have

M = -\frac{f_o}{f_e}

M = -\frac{71}{2.1}

M = - 33.81

Therefore the magnification of this astronomical telescope is -33.81

7 0
3 years ago
When connected to a battery, a lightbulb glows brightly. If the battery is reversed and reconnected to the bulb, the bulb will g
attashe74 [19]

Answer: c) with the same brightness

Explanation: The load in this case the bulb, is not polarized ( it has no positive and negative points) thus any connection relative to the battery (source) will have no effect on it brightness.

Also, brightness is a function of current and in this case the voltage ( from battery) and resistance of load (bulb) is constant, and according to ohms law (V=IR) if the current is constant at the first connection, it will be the same at the reversed connection.

8 0
3 years ago
Do you remove the positive or negative first on a car battery?
nevsk [136]

Answer:

negative at first.

Explanation:

It's important to disconnect the negative side at first, otherwise you can cause an electrical short if positive is removed first.

4 0
1 year ago
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