They give us the cable tension t = 1500 newton. We assume that the mass of the cable is negligible compared to that of the tower.
We have a force t of 1500 Newton. This force has a vertical component on the y axis and a horizontal component on the x axis.
Of these two components of force, we are especially interested in calculating is the magnitude of the vertical component.
If the angle that it forms with the ground is 50 °, then the vertical component of the force is:
Fy = 1500sin (50)
Fy = 1149 N. <1200 N
The wire will not be loose
Hi there!
Recall that:
Given an electric field, the potential difference can be solved by using integration. Similarly:
We can differentiate the electric potential equation to solve for the electric field.
Use the power rule:
Differentiate the given equation.
Or:
To solve this problem it is necessary to apply the concepts related to optical magnification (is the process of enlarging the apparent size, not physical size, of something.). Specifically the angular magnification of an optical telescope is given by
Where,
Focal length of the objective lens in a refractor
Focal length of the eyepiece
Our values are given as
71cm
2.1cm
Replacing we have
Therefore the magnification of this astronomical telescope is -33.81
Answer: c) with the same brightness
Explanation: The load in this case the bulb, is not polarized ( it has no positive and negative points) thus any connection relative to the battery (source) will have no effect on it brightness.
Also, brightness is a function of current and in this case the voltage ( from battery) and resistance of load (bulb) is constant, and according to ohms law (V=IR) if the current is constant at the first connection, it will be the same at the reversed connection.
Answer:
negative at first.
Explanation:
It's important to disconnect the negative side at first, otherwise you can cause an electrical short if positive is removed first.
