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Goshia [24]
2 years ago
11

How many liters of hydrogen are required to react completely with 2.4L of oxygen to form water? 2H2 + O2 --> 2H2O

Chemistry
1 answer:
RoseWind [281]2 years ago
3 0

Answer:

2.4 mole of oxygen will react with 2.4 moles of hydrogen

Explanation:

As we know

1 liter = 1000 grams

2H2 + O2 --> 2H2O

Weight of H2 molecule = 2.016 g/mol

Weight of water = 18.01 gram /l

2 mole of oxygen react with 2 mole of H2

2.4 mole of oxygen will react with 2.4 moles of hydrogen

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If 25 mL of a HCl solution of unknown concentration was neutralized with 10 mL of a 0.30 M NaOH solution, what was the original
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Answer:

0.12 M

Explanation:

Step 1: Write the balanced equation

NaOH + HCl ⇒ NaCl + H₂O

Step 2: Calculate the reacting moles of NaOH

10 mL of a 0.30 M NaOH solution react.

0.010L \times \frac{0.30mol}{L} = 3.0 \times 10^{-3} mol

Step 3: Calculate the reacting moles of HCl

The molar ratio of NaOH to HCl is 1:1. The reacting moles of HCl are 1/1 × 3.0 × 10⁻³ mol = 3.0 × 10⁻³ mol.

Step 4: Calculate the concentration of HCl

3.0 × 10⁻³ mol of HCl are in 25 mL of solution.

M = \frac{3.0 \times 10^{-3} mol}{0.025L} = 0.12 M

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A. animals do not make their own food.

Explanation:

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What are the elements in group two called
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Read 2 more answers
Sodas are not only full of sugar (124 grams/L), but they are also acidic and will dissolve your teeth, composed of hydroxyapatit
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Answer:

The pH of the HCl solution is 3.9

Explanation:

Knowing the molar mass of HCl (36.5g/mol) it is possible to calculate the number of moles of HCl in the solution,

\frac{1.5x10^{-3}g}{36.5g/mol} = 4.1x10^{-5}moles of HCl

HCl is a strong acid and when added to water will form H+ and Cl-, thus the moles of HCl are equal to moles of H+ in 354 mL of water

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The concentration of protons in the solutions is 1.16x10^{-4} M.

The expression used to calculate the pH is

pH = -Log ([H^{+}]) = -Log (1.16x10^{-4} M) = 3.9

Hence, the pH of the HCl solution is 3.9 and Pepsi has a pH of 3.4 approximately, so they have almost the same pH.

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