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3 years ago

Calculate the mass of a

Chemistry

1 answer:

emmainna [20.7K]3 years ago

6 0

Answer:

10.63 × 10^(-24) g

10.62 × 10^(-27) kg

64 daltons

Explanation:

Formula for sulfur (IV) oxide is; SO2

Now,

Atomic mass of Sulphur is 32 while atomic mass of oxygen is 16.

Thus;atomic mass of SO2 is;

32 + (16 × 2) = 64 amu

Now,

1 mole of a substance has 6.02 × 10^(24) molecules

Therefore mass of 1 molecule of SO2 will yield;

Mass(g) = 64/(6.02 × 10^(24)) = 10.63 × 10^(-24) g

Converting to kg, we have;

10.63 × 10^(-24) ÷ 1000 = 10.62 × 10^(-27) kg

Now, converting to Dalton, we know that;

1kg = 6.022 × 10^(26) amu

Thus; 10.62 × 10^(-27) kg will yield;

(10.62 × 10^(-27) × 6.022 × 10^(26))/1 ≈ 64 amu

Now, from conversion;

1 amu = 1 Dalton.

Thus, 64 amu = 64 daltons

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3 years ago

3.5g of a Certain compound X, known to be made of carbon, hydrogen, and perhaps oxygen, and to have a molecular molar mass of 15

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Answer:

C₅H₁₀O₅

Explanation:

1. Calculate the mass of each element in 2.78 mg of X.

(a) Mass of C

$\text{Mass of C} = \text{5.13 g CO}_{2}\times \dfrac{\text{12.01 g C}}{\text{44.01 g }\text{CO}_{2}}= \text{1.400 g C}$

(b) Mass of H

$\text{Mass of H} = \text{2.10 g H$_{2}$O}\times \dfrac{\text{2.016 g H}}{\text{18.02 g H$_{2}$O}} = \text{0.2349 g H}$

(c) Mass of O

Mass of O = 3.5 - 1.400 - 0.2349 = 1.87 g

2. Calculate the moles of each element

$\text{Moles of C = 1400 mg C}\times\dfrac{\text{1 mmol C}}{\text{12.01 mg C }} = \text{116.6 mmol C}\\\\\text{Moles of H = 234.9 mg H} \times \dfrac{\text{1 mmol H}}{\text{1.008 mg H}} = \text{233.1 mmol H}\\\\\text{Moles of O = 1870 mg O} \times \dfrac{\text{1 mmol O}}{\text{16.00 mg O}} = \text{116 mmol O}$

3. Calculate the molar ratios

Divide all moles by the smallest number of moles.

$\text{C: } \dfrac{116.6}{116.6}= 1\\\\\text{H: } \dfrac{233.1}{116.6} = 1.999\\\\\text{O: } \dfrac{116}{116.6} = 1.00$

4. Round the ratios to the nearest integer

C:H:O = 1:2:1

5. Write the empirical formula

The empirical formula is CH₂O.

6. Calculate the molecular formula.

EF Mass = (12.01 + 2.016 + 16.00) u = 30.03 u

The molecular formula is an integral multiple of the empirical formula.

MF = (EF)ₙ

$n = \dfrac{\text{MF Mass}}{\text{EF Mass }} = \dfrac{\text{150 u}}{\text{30.03 u}} = 5.00 \approx 5$

MF = (CH₂O)₅ = C₅H₁₀O₅

The molecular formula of X is C₅H₁₀O₅.

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