Which of the 4 macromolecules is the most important for a cell to carry out metabolism and maintain homeostasis?

A student carefully drops a 9.0 g solid Zn pellet initially at 50.0°C into an insulated cup containing 30.0 g of water at 27.8°C

jekas [21]

Answer: choice B

Explanation: Heat flows from high to low. After you convert the Celsius into kelvin the Zn pellet has 323K and the water has 301K which results the transfer of the heat energy of the pallet to the water. ( you don’t have to convert, but it just make it easier) hope this helped you :)

3 0

3 years ago

Read 2 more answers

HELP I HAVE 14 MINUTES!!

ki77a [65]

Answer:

2 one

Explanation:

is right coz I think

4 0

3 years ago

Read 2 more answers

Non-conjugated β, γ-unsaturated ketones, such as 3-cyclohexenone, as in base-catalyzed equilibrium with their α,β-unsaturated is

uranmaximum [27]

Answer:

See the attached file for the structure.

Explanation:

Find attached for the explanation

7 0

3 years ago

Given the following balanced equation, if the rate of O2 loss is 3.64 × 10-3 M/s, what is the rate of formation of SO3? 2 SO2(g)

Fynjy0 [20]

Answer:

Rate of formation of SO₃ $[\frac{d[SO_{3}] }{dt}]$ = 7.28 x 10⁻³ M/s

Explanation:

According to equation 2 SO₂(g) + O₂(g) → 2 SO₃(g)

Rate of disappearance of reactants = rate of appearance of products

⇒ $-\frac{1}{2} \frac{d[SO_{2} ]}{dt} = -\frac{d[O_{2} ]}{dt}=\frac{1}{2} \frac{d[SO_{3} ]}{dt}$ -----------------------------(1)

Given that the rate of disappearance of oxygen = $-\frac{d[O_{2} ]}{dt}$ = 3.64 x 10⁻³ M/s

So the rate of formation of SO₃ $[\frac{d[SO_{3}] }{dt}]$ = ?

from equation (1) we can write

$\frac{d[SO_{3}] }{dt} = 2 [-\frac{d[O_{2}] }{dt} ]$

⇒ $\frac{d[SO_{3}] }{dt}$ = 2 x 3.64 x 10⁻³ M/s

⇒ $[\frac{d[SO_{3}] }{dt}]$ = 7.28 x 10⁻³ M/s

∴ So the rate of formation of SO₃ $[\frac{d[SO_{3}] }{dt}]$ = 7.28 x 10⁻³ M/s

7 0

3 years ago

Explain why water is polar. Check all that apply. View Available Hint(s) Water is known as a polar molecule because Check all th

sineoko [7]

Answer:

The correct statements that you must check are:

The oxygen atom has a greater attraction for electrons than the hydrogen atom does (second statement).

The electrons of the covalent bond are not shared equally between the hydrogen and oxygen atoms (fourth statement).

Explanation:

Electronegativity is the relative ability of an atom to pull the electrons in a covalent bond.

Hydrogen has an electronegativity of 2.20 and oxygen has 3.44. That means that oxygen attracts the electrons more strongly than hydrogen does (second statement).

As consequence, the electrons in the covalent bond H - O of water are not shared equally (fourth statement): the electron density will be higher around the O atoms.

Of course, this discards the statement telling that hydrogen atom attracts electrons much more strongly than the oxygen atom, and the statement telling that hydrogen and oxigen have same electronegativity.

Such difference in electron densities creates a dipole moment, so you discard the last statement (that the water dipole moment is equal to zero).

7 0

3 years ago