The kinda of energy the involves the flow of positive charge is Electrical
Weathering and chemical substance weathering
Answer : The amount of heat released, 45.89 KJ
Solution :
Process involved in the calculation of heat released :
Now we have to calculate the amount of heat released.
![Q=[m\times c_{p,l}\times (T_{final}-T_{initial})]+\Delta H_{fusion}+[m\times c_{p,s}\times (T_{final}-T_{initial})]](https://tex.z-dn.net/?f=Q%3D%5Bm%5Ctimes%20c_%7Bp%2Cl%7D%5Ctimes%20%28T_%7Bfinal%7D-T_%7Binitial%7D%29%5D%2B%5CDelta%20H_%7Bfusion%7D%2B%5Bm%5Ctimes%20c_%7Bp%2Cs%7D%5Ctimes%20%28T_%7Bfinal%7D-T_%7Binitial%7D%29%5D)
where,
Q = amount of heat released = ?
m = mass of water = 27 g
= specific heat of liquid water = 4.184 J/gk
= specific heat of solid water = 2.093 J/gk
= enthalpy change for fusion = 40.7 KJ/mole = 40700 J/mole
conversion : 
Now put all the given values in the above expression, we get
![Q=[27g\times 4.184J/gK\times (314-273)k]+40700J+[27g\times 2.093J/gK\times (273-263)k]](https://tex.z-dn.net/?f=Q%3D%5B27g%5Ctimes%204.184J%2FgK%5Ctimes%20%28314-273%29k%5D%2B40700J%2B%5B27g%5Ctimes%202.093J%2FgK%5Ctimes%20%28273-263%29k%5D)
(1 KJ = 1000 J)
Therefore, the amount of heat released, 45.89 KJ
Step 1
Molarity is defined as Moles of solute (NH3) divided by the volume of the solution in L
Molarity (mol/L or M) = moles of NH3/volume of the solution (L) (1)
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Step 2
The moles of solute (NH3):
0.500 % by mass means:
0.500 g/100 g solution
Moles of NH3 are calculated as:
Mass of NH3/molar mass NH3 = 0.500 g/17.0 g/mol = 0.029 moles NH3
(molar mass NH3 = 17.0 g/mol)
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Step 2
The volume of solution:
Volume is calculated from density
Density = mass solution/volume of solution
Volume = mass of solution/density = 100 g solution/0.996 g/mL => Volume = 100.4 mL
1L = 1000 mL => V = 100.4 mL = 0.1004 L
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Step 4
From (1)
Molarity = moles of NH3/volume of the solution (L) = 0.029 moles NH3/0.1004 L = 0.289 mol/L
Answer: M = 0.289 M or mol/L
According to the conversation of mass, mass cannot be created or destroyed. This means whatever is done to one side, must be done to the other.
There are 4 Phosphorus atoms on the left, there must be 4 on the right. To do this, you must multiply the P2O3 by 2 to get 4 Phosphorus atoms and 6 Oxygen atoms. Now to balance the Oxygen atoms, you must multiply the oxygen atoms on the left by 3.
1 P4 + 3 O2 —-> 2 P2O3
Lastly, this equation type is synthesis (combination) because two reactants are becoming a single product.
