Answer: B. you will need 53.2 g Cl2 for complete reaction and will produce 66.7 g of AlCl3.
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles.
To calculate the moles, we use the equation:
The balanced reaction is:
2 moles of aluminium react with= 3 moles of chlorine
Thus 0.5 moles of aluminium react with= moles of chlorine
Mass of chlorine=
2 moles of aluminium produce = 2 moles of aluminium chloride
Thus 0.5 moles of aluminium react with= moles of aluminium chloride
Mass of aluminium chloride=
Thus 53.2 g of chlorine is used and 66.7 g of aluminium chloride is produced.
Answer:
The correct answer is 8.786 g CaCO₃
Explanation:
The balanced reaction is the following:
CaCl₂(ac) + K₂CO₃(ac) → CaCO₃(s) + 2 KCl(ac)
From the stoichiometry, 1 mol of CaCl₂ (111 g) reacts with 1 mol of K₂CO₃ (138 g) to form 1 mol CaCO₃(100 g) and 2 moles of KCl (149 g).
The stoichiometric ratio CaCl₂/K₂CO₃ is: 111 g/138 g= 0.80 g CaCl₂/K₂CO₃.
We have 14.584 g CaCl₂ and 12.125 g K₂CO₃, which gives a ratio of: 14.584g/12.125 g= 1.2 g CaCl₂/K₂CO₃.
0.8 ∠ 1.2 ⇒ K₂CO₃ is the limiting reactant
We use the limiting reactant to calculate the grams of CaCO₃ produced. For this, we know that from 138 g K₂CO₃ 100 g of CaCO₃ are produced. So, we multiply the amount of K₂CO₃ by this stoichiometric ratio to obtain the grams of CaCO₃ produced:
12.125 g K₂CO₃ x 100 g CaCO₃/138 g K₂CO₃= 8.786 g CaCO₃
Therefore, the theoretical yield of CaCO₃ is 8.786 g.
The person above is correct
Answer : The molar heat capacity at constant volume and constant pressure is 29.9 J/mol.K and 38.2 J/mol.K respectively.
Explanation :
Formula used for specific heat at constant volume :
where,
= heat = 229 J
n = moles of gas = 3.0 mol
= molar heat capacity at constant volume = ?
= change in temperature = 2.55 K
Now put all the given value in the above formula, we get:
The molar heat capacity at constant volume is 29.9 J/mol.K
Now we have to calculate the molar heat capacity at constant pressure.
Formula used :
where,
= molar heat capacity at constant volume = 29.9 J/mol.K
= molar heat capacity at constant pressure = ?
R = gas constant = 8.314 J/mol.K
Now put all the given value in the above formula, we get:
The molar heat capacity at constant pressure is 38.2 J/mol.K
Answer:
we need we need to calculate normality of solution to find out gram equivalent of solution