Answer: 0.147 grams
Explanation:
To calculate the moles :
According to stoichiometry :
2 moles of 
require = 2 moles of ![NaOH/tex]Thus 0.049 moles of [tex]Al](https://tex.z-dn.net/?f=NaOH%2Ftex%5D%3C%2Fp%3E%3Cp%3EThus%200.049%20moles%20of%20%5Btex%5DAl)
will require=
of 
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
As 2 moles of give = 3 moles of 
Thus 0.049 moles of give =
of
Mass of 
Thus 0.147 g of will be produced from the given masses of both reactants.
Answer:
<h2><u>Of moles of NH4NO3 = 16/80 i.e. 0.2 moles of Ammonium Nitrate. 1 molecule of NH4NO3 contains 1 atom of N. Hence, 1 mole of NH4NO3 would contain 1 mole of Nitrogen atoms and therefore 0.2 moles of NH4NO3 should contain 0.2 moles of Nitrogen atoms</u>.</h2>
Explanation:
Answer:
its not inclusive fitness which is confusing but
Explanation:
ill give the answer when I finish the test
Answer:
Fluorine azide or triazadienyl fluoride (FN3) is a yellow green gas composed of nitrogen and fluorine with formula FN3. It is counted as an interhalogen compound, as the azide functional group is termed a pseudohalogen. It resembles ClN3, BrN3, and IN3 in this respect.
Explanation:
In a phase diagram that I have attached, the line marked in between ice and water (yellow and blue) is the conditions in which solid (ice) and liquid (Water) can coexist. As the graph shows, solid ice and liquid water coexist most when the temperature is zero, which should make sense since ice melts at 0, and water freezes as well at 0 degrees celsius.
