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3 years ago

kayla spent 1/6 of her money on clothes. She had $250 remaining. What was the cost of the clothes Kayla bought?

Mathematics

1 answer:

d1i1m1o1n [39]3 years ago

6 0

Answer

$50

Step-by-step explanation:

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The quotient of a number and -7, decreased by 2, is 10

Mars2501 [29]

Answer:

wouldnt it be -9

Step-by-step explanation:

beacuse negitive 7-2 is negitive 9 bc negitive plus a negitive is a negitive ?? right

3 0

3 years ago

Simplify this for me thanks u

almond37 [142]

$4n + 3(n - 5) + 2 \\ \\ = 4n + 3n - 15 + 2\\ \\ = 7n - 13$

<h3>Option B</h3>

<h3>Hope This Helps You ❤️</h3>

3 0

3 years ago

Hannah's hair was 18 inches long .Three years later it was 33 inches long. What was the percent increase,to the nearest hundredt

daser333 [38]

In document below

8hh4oo$8

5 0

3 years ago

Read 2 more answers

40 points, please help with all of them

Kitty [74]

Answer:

$\large\boxed{Q1.\ \text{2 times greater}}\\\\\boxed{Q2.\ J. 3}\\\\\boxed{Q3.\ B. -\dfrac{4}{5}}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

Q1.

We have the equation of a line <em>p </em>in the standard form

$4x-3y=7$

Convert to the slope-intercept form:

$4x-3y=7$ <em>subtract 3x from both sides</em>

$-3y=-4x+7$ <em>divide both sides by (-3)</em>

$y=\dfrac{4}{3}x-\dfrac{7}{3}$

The slope $m_1=\dfrac{4}{3}$

From the table we have the points (4, 3) and (7, 5). Calculate the slope of line <em>q</em>:

$m_2=\dfrac{5-3}{7-4}=\dfrac{2}{3}$

Divide the slope of <em>p</em> by the slope of <em>q</em>:

$\dfrac{4}{3}:\dfrac{2}{3}=\dfrac{4}{3}\cdot\dfrac{3}{2}=2$

Q2.

Parallel line have the same slope. Therefore, if we have the equation of the line in the slope-intercept form, then we have the slope:

$y=3x+2\to m=3$

Q3.

Parallel line have the same slope.

Calculate the slope from given points (-11, 5) and (-6, 1):

$y=\dfrac{1-5}{-6-(-11)}=\dfrac{-4}{-6+11}=\dfrac{-4}{5}=-\dfrac{4}{5}$

6 0

3 years ago

((81x^3 y^(-1/3))^1/4)/(x^2 y)^1/4 simplify

malfutka [58]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}
\\\\\\
\left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\
-------------------------------\\\\$

$\bf \cfrac{\left( 81x^3y^{-\frac{1}{3}} \right)^{\frac{1}{4}}}{(x^2y)^{\frac{1}{4}}}\implies \cfrac{81^{\frac{1}{4}}x^{3\cdot {\frac{1}{4}}}y^{-\frac{1}{3}\cdot {\frac{1}{4}}}}{x^{2\cdot {\frac{1}{4}}}y^{\frac{1}{4}}}\implies
\cfrac{81^{\frac{1}{4}}x^{\frac{3}{4}}y^{-\frac{1}{12}}}{x^{\frac{2}{4}} y^{\frac{1}{4}}}$

$\bf \cfrac{81^{\frac{1}{4}}x^{\frac{3}{4}}x^{-\frac{2}{4}}}{ y^{\frac{1}{4}}y^{\frac{1}{12}}}\implies \cfrac{(3^4)^{\frac{1}{4}}x^{\frac{3}{4}-\frac{2}{4}}}{y^{\frac{1}{4}+\frac{1}{12}}}\implies \cfrac{3^{4\cdot \frac{1}{4}}x^{\frac{1}{4}}}{y^{\frac{4}{12}}}\implies \cfrac{3^{\frac{4}{4}}x^{\frac{1}{4}}}{y^{\frac{1}{3}}}
\\\\\\
\cfrac{3\sqrt[4]{x}}{\sqrt[3]{y}}$

7 0

3 years ago