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otez555 [7]
3 years ago
15

BRAINLIEST

Chemistry
2 answers:
Nat2105 [25]3 years ago
7 0
I believe that it most likely would be D.
jeyben [28]3 years ago
4 0

Answer:

Option : C

Hope it helps you! ...

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When zn(oh)2(s) was added to 1.00 l of a basic solution, 1.09×10−2 mol of the solid dissolved. what is the concentration of oh−
uysha [10]
The concentration of the basic solution is determined by:

N = (number of moles / volume of solution) 

number of moles = 1.09 x 10^-2 mol
volume of solution = 1 liter
N of basic solution = 1.09 x 10^-2 mol / 1 liter
N = 1.09 x 10^-2 mol/L

The initial concentration of Zn (OH)2 is 0; the basic solution is 1.09x10^-2 M, then the concentration of OH in the final solution is 1.09x10^-2 M



7 0
3 years ago
Read 2 more answers
PLZ HELP ASAP!!!!!
aleksley [76]
C. 346 g hope this helps you
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Answer:

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Explanation:

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