Question

4. Calculate the concentration of NaCl in a solution prepared by diluting 2 mL of 0.05 M NaCl to a total volume of 10 mL with deionized water. What is the total concentration of ions in the diluted solution

Answer 1

Answer:

Molarity of NaCl = Molarity of sodium ions = Molarity of chloride ions = 0.01 M

Explanation:

Considering

$Molarity_{diluted\ solution}\times Volume_{diluted\ solution}=Molarity_{stock\ solution}\times Volume_{stock\ solution}$

Given  that:

$Molarity_{diluted\ solution}=?$

$Volume_{diluted\ solution}=10\ mL$

$Volume_{stock\ solution}=2\ mL$

$Molarity_{stock\ solution}=0.05\ M$

So,  

$Molarity_{diluted\ solution}\times 10\ mL=0.05\ M\times 2\ mL$

$Molarity_{diluted\ solution}=0.01\ M$

Molarity of NaCl = Molarity of sodium ions = Molarity of chloride ions = 0.01 M