Answer:
The swirling yellow solid formed is lead iodide (PbI₂).
Explanation:
- The reaction of potassium iodide (KI) with lead nitrate (Pb(NO₃)₂) will produce lead iodide (PbI₂) and potassium nitrate (KNO₃) according to the equation:
2KI + Pb(NO₃)₂ → PbI₂↓ + 2KNO₃
- Lead iodide (PbI₂) is a yellow swirling precipitate that is formed from the reaction.
<span>Answer: the average kinetic energy of the particles.
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<span>Jusitification:
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<span>Temperature and heat energy are closely related.
</span><span />
<span>While heat is the kinetic energy of the particles of a substance which is transferred from a hotter substance to a cooler one, the temperature is a measure of the average kinetic energy of the particles in a substance.
</span><span />
<span>The relatively high kinetic energy the particles of a warm substance is transferred to the cooler one by the motion (vibration or translation) of the atoms of molecules. The energy transferred is heat energy.</span>
Answer:
V₂ = 0.656 L
Explanation:
Given data:
Initial volume = 3.5 L
Initial pressure = 2.5 KPa
Final volume = ?
Final pressure = 100 mmHg (100/7.501=13.33 KPa)
Solution:
The given problem will be solved through the Boyle's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
2.5 KPa × 3.5 L = 13.33 KPa × V₂
V₂ = 8.75 KPa. L/13.33 KPa
V₂ = 0.656 L
Explanation:
Immunoglobulin M is the first antibody produced on initial exposure to an antigen. It is also known as IgM.
It occurs as a primary response to the antigens against a particular baterium or virus. It is pentavalent in nature and has ten binding sites for antigens.
Therefore, it is concluded that when the body identifies a bacterium or a virus, it releases the antibody IgM.
