An undergraduate weighed out 20grams of sodium hydroxide pellets. If Na =23, O = 16 andH = 1, What is the mole of this sodium hy
1 answer:
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Answer: 25.8 g of will be produced from the decomposition of 73.4 g of
Explanation:
To calculate the moles :
The balanced chemical reaction is:
According to stoichiometry :
2 moles of produce = 3 moles of
Thus 0.242 moles of will produce= of
Mass of =
Thus 25.8 g of will be produced from the decomposition of 73.4 g of
<u>Answer:</u> The mass percent of hydrogen in methyl acetate is 8 %
<u>Explanation:</u>
The given chemical formula of methyl acetate is
To calculate the mass percentage of hydrogen in methyl acetate, we use the equation:
Mass of hydrogen = (6 × 1) = 6 g
Mass of methyl acetate = [(3 × 12) + (6 × 1) + (2 × 16)] = 74 g
Putting values in above equation, we get:
Hence, the mass percent of hydrogen in methyl acetate is 8 %