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Flauer [41]
3 years ago
5

PROBLEM: Juan hires an electrician. Juan pays a one-time fee of $30. Juan also pays $45 for each hour the electrician works. A.

Write a function that can be used to find the total charge, c, Juan will pay when the electrician works, h, hours. Y=mx+b B. How much will Juan pay if it takes the electrician 6 1/2 hours to complete the job? (Vou should have 9 answers in question 2​
Mathematics
1 answer:
Sidana [21]3 years ago
6 0

Answer: a. c = 30 + 45h

b. $322.50

Step-by-step explanation:

A. Write a function that can be used to find the total charge, c, Juan will pay when the electrician works, h, hours.

This will be calculated as:

c = 30 + 45h

B. How much will Juan pay if it takes the electrician 6 1/2 hours to complete the job?

Using the expression,

c = 30 + 45h

c = 30 + 45(6 1/2)

c = 30 + 292 1/2

c = 322.50

Therefore, Juan will pay $322.50

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borishaifa [10]

Answer:

The given statement is true because the person they did their steps correctly

a) Locate a point C so that ABC is a right triangle with m ACB ∠ = ° 90 and the measure of one of the acute angles in the triangle is 45° .

b) Locate a point D so that ABD is a right triangle with m ADB ∠ = ° 90 and

the measure of one of the acute angles in the triangle is30° .

c) Locate a point E so that ABE is a right triangle with m AEB ∠ = ° 90 and

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d) Find the distance between point C and the midpoint of segment AB .

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3 years ago
laura compro un microondas por 216.750 y una lavadora 910.350 si le rebajaron 43.350 en la compra y el resto la paga en 15 plazo
Alecsey [184]
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2 years ago
A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of
Ivenika [448]

The equation for the height of the rocket at time t given

h= -16t^2+192t

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

h= -16t^2+192t

560 = -16t^2+192t

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

560 = -16(t^2 - 12t)

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

560/-16 = -16(t^2-12t)/-16

-35 = t^2 -12t

Now we will move -35 to the righ side by adding 35 to both sides.

-35+35 = t^2-12t+35

0 = t^2 -12t+35

t^2-12t+35 = 0

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

t^2-12t+35 =0

(t-5)(t-7) =0

So by using zero product property we will get

t-5 =0

t-5+5 = 0+5

t=5

Also t-7 =0

t-7+7 = 0+7

t=7

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

h= -16t^2+192t

0= -16t^2 + 192 t

0 = -16(t^2-12t)

-16(t^2-12t) = 0

We will move -16 to the other side by dividing it to both sides.

-16(t^2-12t)/-16 = 0/-16

t^2-12t = 0

We will take out the common factor t from the left side. By taking out t we will get,

t(t-12) = 0

We will use zero product property now. By using that we will get,

t = 0

ans also t-12 = 0

t-12+12 = 0+12

t = 12

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

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notsponge [240]

Hey there!

A perpendicular line's slope to another line is always the negative reciprocal of slope.

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