Ask question

Ask question

All categories

3 years ago

11

The polycarbonate shell functions as all of the following except:

1 answer:

krok68 [10]3 years ago

6 0

Answer:

what are the answers expect what?

Explanation:

Polycarbonate is commonly used in eye protection, as well as in other projectile-resistant viewing and lighting applications that would normally indicate the use of glass, but require much higher impact-resistance. Polycarbonate lenses also protect the eye from UV light.

You might be interested in

A body is moving with simple harmonic motion. It's velocity is recorded as being 3.5m/s when it is at 150mm from the mid-positio

natima [27]

Answer:

1) A=282.6 mm

2) $a_{max}=60.35\ m/s^2$

3)T=0.42 sec

4)f= 2.24 Hz

Explanation:

Given that

V=3.5 m/s at x=150 mm ------------1

V=2.5 m/s at x=225 mm ------------2

Where x measured from mid position.

We know that velocity in simple harmonic given as

$V=\omega \sqrt{A^2-x^2}$

Where A is the amplitude and ω is the natural frequency of simple harmonic motion.

From equation 1 and 2

$3.5=\omega \sqrt{A^2-0.15^2}$ ------3

$2.5=\omega \sqrt{A^2-0.225^2}$ --------4

Now by dividing equation 3 by 4

$\dfrac{3.5}{2.5}=\dfrac {\sqrt{A^2-0.15^2}}{\sqrt{A^2-0.225^2}}$

$1.96=\dfrac {{A^2-0.15^2}}{{A^2-0.225^2}}$

So A=0.2826 m

A=282.6 mm

Now by putting the values of A in the equation 3

$3.5=\omega \sqrt{A^2-0.15^2}$

$3.5=\omega \sqrt{0.2826^2-0.15^2}$

ω=14.609 rad/s

Frequency

ω= 2πf

14.609= 2 x π x f

f= 2.24 Hz

Maximum acceleration

$a_{max}=\omega ^2A$

$a_{max}=14.61 ^2\times 0.2826\ m/s^2$

$a_{max}=60.35\ m/s^2$

Time period T

$T=\dfrac{2\pi}{\omega}$

$T=\dfrac{2\pi}{14.609}$

T=0.42 sec

8 0

4 years ago

A priority encoder circuit has four inputs,X3-0. The circuit has three outputs: Z,Y1-0. If any of X3-0is 1, then Zis 1, and Y re

sladkih [1.3K]

Answer:

Detailed solution is given below:

3 0

3 years ago

What scale model proves the initial concept?

Tju [1.3M]

Answer: A prototype

Explanation:

5 0

3 years ago

The current drawn by fluorescent lighting has a high total harmonic distortion. For this case, THD is calculated to be 88%. The

Alona [7]

Answer:

displacement power factor is 0.959087

Explanation:

given data

THD = 88%

true power factor = 0.72

solution

we get here total harmonic distribution THD is express as here

THD = $\sqrt{\frac{1}{g^2}-1}$ ..............1

her g is distortion factor

so put here value and we will get g that is

0.88² = $\frac{1}{g^2} -1$

solve it we get

g = 0.750714

and

displacement power factor is express as

DPF = $\frac{PF}{g}$ .................2

put here value and we will get

DPF = $\frac{0.72}{0.750714}$

DPF = 0.959087

3 0

3 years ago

Citations must be contested within_____working days of the notice of proposed penalty. a)-15 b)-10 c)-30 d)-7

seropon [69]

Answer:

30

Explanation:

Legally that's when you have to respond

8 0

3 years ago