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Bezzdna [24]
3 years ago
11

The polycarbonate shell functions as all of the following except:

Engineering
1 answer:
krok68 [10]3 years ago
6 0

Answer:

what are the answers expect what?

Explanation:

Polycarbonate is commonly used in eye protection, as well as in other projectile-resistant viewing and lighting applications that would normally indicate the use of glass, but require much higher impact-resistance. Polycarbonate lenses also protect the eye from UV light.

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A network address of 172.16.0.0 /12 has been given. Which of the following accurately describes this network? (select one or mor
ludmilkaskok [199]

Answer:

B and E is correct.

Explanation:

Given that network address

172.16.0.0/12

This is class B network type.

The ending of this network will be 172.31.255.255

In IP version 4 there are four following type of classes

1)Class A (0-127)

2)Class B (128-191)

3)Class C (191-223)

4)Class D(224-239)

5)Class E (240-255)

Generally class A,B,C and D are used.

So our options B and E is correct.

3 0
3 years ago
A(n) ___ is an electric device that uses electromagnetism to change (step up or step down) AC voltage from one level to another.
Pie

Answer:

A transformer is an electric device that uses electromagnetism to change voltage from one level to another or to isolate one voltage from another.

7 0
3 years ago
How does accenture generate value for clients through agile and devops?
Stells [14]
By permanently locking in stakeholder requirements during a project's planning phase
4 0
3 years ago
A subsurface exploration report shows that the average water content of a fine-grained soil in a proposed borrow area is 22% and
Morgarella [4.7K]

Answer:

shrinkage ratio  = 1.538

Explanation:

given data

water content = 22 %

dry density γ = 82 pcf

required dry density specified γ' = 96 pcf

required to produce = 50,000 yd³  = 50000 × 27 = 1350,000 ft³

solution

we get here first volume of borrow pit that is we know that

dry density ∝  \frac{1}{volume}  

so \frac{\gamma d}{\gamma 'd}  = \frac{v'}{v}

\frac{82}{96}  = \frac{1350000}{v}

v = 1580487.8 ft³

v = 58536.58 yd³

so here

shrinkage ratio will be as

shrinkage ratio = \frac{96}{62.4}  

shrinkage ratio  = 1.538

6 0
3 years ago
Listed below are snippets from a prgram to perform input validation for
leva [86]

Answer:

#include <iostream>

#include <string>

#include "user.h"

#include "password.h"

using namespace Authenticate;

using namespace std;

int main()

{

inputUserName();

inputPassword();

cout << "Your username is " << getUserName() <<

" and your password is: " <<

getPassword() << endl;

return 0;

}

user.h:

#ifndef USER_H

#define USER_H

#include <string>

using namespace std;

namespace Authenticate

{

namespace

{

bool isvalid();

}

void inputUserName();

string getUserName();

}

#endif

user.cpp:

#include <iostream>

#include "user.h"

namespace Authenticate

{

string username="";

namespace

{

bool isvalid()

{

if(username.length() == 8)

return true;

else

return false;

}

}

void inputUserName(){

do

{

cout << "Enter your username (8 letters only)" << endl;

cin >> username;

}

while(!isvalid());

}

string getUserName()

{

return username;

}

}

password.h:

#ifndef PASSWORD_h

#define PASSWORD_h

#include <string>

using namespace std;

namespace Authenticate

{

namespace

{

bool isValid();

}

void inputPassword();

string getPassword();

}

#endif

password.cpp:

#include <iostream>

#include <string>

using namespace std;

namespace Authenticate

{

string password="";

namespace

{

bool isValid()

{

if(password.length() >= 8)

{

for(int i=0; i<password.length(); i++)

if(password[i] >= '0' && password[i] <= '9')

return true;

return false;

}

else

return false;

}

}

void inputPassword(){

do

{

cout << "Enter your password (at least 8 characters " <<

"and at leat one non-letter)" << endl;

cin >> password;

}

while(!isValid());

}

string getPassword()

{

return password;

}

}

3 0
3 years ago
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